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Chapter 19: Problem 2626

A n-p-n transistor is used in common emitter made in an amplifier it. A change of \(40 \mu \mathrm{A}\) in the base current changes the output current by $2 \mathrm{~mA}\( and \)0.04 \mathrm{~V}$ in input voltage. If a load of \(6 \mathrm{k} \Omega\) is used, then the voltage gain of the amplifier is (A) 100 (B) 200 (C) 300 (D) 400

Short Answer

Expert verified
The voltage gain of the amplifier is 300 (C).

Step by step solution

01

Find the change in output voltage

Given the change in base current and change in output current, we can calculate the change in output voltage. When the load of \(6\ \text{k}\Omega\) is used, the change in output voltage can be found using Ohm's law, which states that the voltage across a resistor is equal to the product of the current and its resistance: ΔV_output = ΔI_output × R_load, where ΔI_output is the change in output current and R_load is the load.
02

Calculate the change in output voltage

Given ΔI_output = \(2\) mA and R_load = \(6\) kΩ, we can compute the change in output voltage: ΔV_output = (\(2\) mA) × (\(6\) kΩ) = \(12\) V.
03

Determine the voltage gain

The voltage gain of an amplifier (A) is defined as the ratio of the change in output voltage to the change in input voltage: A = ΔV_output / ΔV_input We are given that the change in input voltage, ΔV_input is \(0.04\) V. Now we can find the voltage gain: A = (\(12\) V) / (\(0.04\) V) = \(300\). So, the voltage gain of the amplifier is 300 (C).

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Most popular questions from this chapter

From the following semi-conductor devices, operates in forward bias only. (A) Varactar diode (B) Zenger diode (C) Light emitting diode (D) photo-diode

Direction for Assertion - Reason type questions (A) If both Assertion and Reason are true and reason is the correct explanation of assertion. (B) If both Assertion and Reason are true but Reason is not the correct explanation of assertion. (C) If Assertion is true but Reason is false (D) If both assertion and reason are false A : A transistor amplifier circuit in common emitter configuration has low input impedance \(\mathrm{R}\) : Base-emitter junction is forward biased (A) (B) (C) (D)

A potential barrier of \(0.6 \mathrm{~V}\) exists across a P-N junction. If the depletion region is \(1 \mu \mathrm{m}\) wide, what is the intensity of electric field in the region? (A) \(4 \times 10^{5} \mathrm{Vm}^{-1}\) (B) \(5 \times 10^{5} \mathrm{Vm}^{-1}\) (C) \(6 \times 10^{5} \mathrm{Vm}^{-1}\) (D) \(2 \times 10^{5} \mathrm{Vm}^{-1}\)

Reverse bias applied on a junction diode: (A) raises the potential barrier (B) increases majority charge carrier current (C) lowers the potential barrier (D) increases the temperature of junction

What kind of device is a diode? (A) Bilateral (B) Linear (C) Nonlinear (D) Unipolar
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