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Chapter 2: Problem 193

What does the speedometer measure kept in motorbike? (A) Average Velocity (B) Average speed (C) instantaneous speed (D) instantaneous Velocity

Short Answer

Expert verified
(C) Instantaneous Speed

Step by step solution

01

Understand the definitions

To find the most accurate answer, we first need to understand the key differences between the terms given in the options: 1. Average Velocity: The distance covered in a particular direction divided by the time taken. 2. Average Speed: The total distance traveled divided by the time taken, irrespective of the direction. 3. Instantaneous Speed: The speed of an object at a specific point in time. 4. Instantaneous Velocity: The velocity of an object at a specific point in time, including both the speed and direction.
02

Identify the purpose of a speedometer

A speedometer in a motorbike is designed to display the current (instantaneous) speed of the motorbike for the rider. It does not provide information about the direction of travel, nor does it measure average speed or velocity over a period of time.
03

Choose the correct answer

Based on the understanding of the purpose of a speedometer, we can choose the appropriate answer: (C) Instantaneous Speed The speedometer measures the instantaneous speed of the motorbike.

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Most popular questions from this chapter

A car moving over a straight path covers a distance \(\mathrm{x}\) with constant speed \(10 \mathrm{~ms}^{-1}\) and then the same distance with constant speed of \(\mathrm{V}_{2}\). If average speed of the car is \(16 \mathrm{~ms}^{-1}\), then \(\mathrm{V}_{2}=\ldots\) (A) \(30 \mathrm{~ms}^{-1}\) (B) \(20 \mathrm{~ms}^{-1}\) (C) \(40 \mathrm{~ms}^{-1}\) (D) \(25 \mathrm{~ms}^{-1}\)

A freely falling particle covers a building of \(45 \mathrm{~m}\) height in one second. Find the height of the point from where the particle was released. \(\left[\mathrm{g}=10 \mathrm{~ms}^{-2}\right]\) (A) \(120 \mathrm{~m}\) (B) \(125 \mathrm{~m}\) (C) \(25 \mathrm{~m}\) (D) \(80 \mathrm{~m}\)

The angle between \(i \wedge+j \wedge\) and \(z\) axis is \(\ldots\) (A) 0 (B) 45 (C) 90 (D) 180

The resultant of two vectors \(\mathrm{A}^{\rightarrow}\) and \(\mathrm{B}^{\rightarrow}\) (A) can be smaller than \(\mathrm{A}-\mathrm{B}\) in magnitude (B) can be greater than \(\mathrm{A}+\mathrm{B}\) in magnitude (C) can't be greater than \(\mathrm{A}+\mathrm{B}\) or smaller than \(\mathrm{A}-\mathrm{B}\) in magnitude (D) none of above is true

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