Which from the following is a scalar? (A) Electric current (B) Velocity (C) acceleration (D) Electric field

Short Answer

Expert verified
Option (A) Electric current is the scalar quantity among the given options, as it only has magnitude and does not have a specific direction.

Step by step solution

01

Analyze Option (A) Electric current

Electric current is the flow of electric charge through a conductor or circuit. It is measured in Amperes (A) and only has a magnitude, with no specific direction. Therefore, electric current is a scalar quantity.
02

Analyze Option (B) Velocity

Velocity is a measure of how fast an object is moving in a particular direction. It has both magnitude and direction, so it's a vector quantity, not a scalar.
03

Analyze Option (C) Acceleration

Acceleration is the rate of change of velocity with time. Since velocity is a vector quantity, acceleration is also a vector, as it involves both magnitude and direction. So, acceleration is not a scalar.
04

Analyze Option (D) Electric field

Electric field is a vector quantity that represents the force felt by a charged particle in a given area. It has both magnitude (Newtons per Coulomb, N/C) and direction. Thus, electric field is not a scalar.
05

Identify the scalar quantity

From our analysis of each option, we can conclude that Option (A) Electric current is the scalar quantity among the given options.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find a unit vector perpendicular to both \(\mathrm{A}^{\rightarrow}\) and \(\mathrm{B}^{\rightarrow}\) (A) $\left[\left(\mathrm{A}^{\rightarrow} \cdot \mathrm{B}^{\rightarrow}\right) / \mathrm{AB}\right]$ (B) $\left[\left(\mathrm{A}^{\rightarrow} \times \mathrm{B}^{-}\right) /(\mathrm{AB} \sin \theta)\right]$ (C) $\left[\left(\mathrm{A}^{\rightarrow} \times \mathrm{B}^{\rightarrow}\right) /(\mathrm{AB} \cos \theta)\right]$ (D) $\left[\left(\mathrm{A}^{\rightarrow} \cdot \mathrm{B}^{\rightarrow}\right) /(\mathrm{AB} \sin \theta)\right]$

A balloon is going vertically up with velocity \(12 \mathrm{~m} / \mathrm{s}\). When it is at height of \(65 \mathrm{~m}\) above the ground, it releases a stone. In how much time the stone will reach the ground. (A) \(\sqrt{13} \mathrm{~s}\) (B) \(10 \mathrm{~s}\) (C) \(5 \mathrm{~s}\) (D) \(6 \mathrm{~s}\)

What is the angle between \(\mathrm{Q}^{-}\) and the resultant of \(\mathrm{P}^{-}+\mathrm{Q}^{\rightarrow}\) and \(\mathrm{Q}^{\rightarrow}-\mathrm{P}^{\rightarrow}\) (A) \(90^{\circ}\) (B) \(60^{\circ} \quad\) (C) 0 (D) \(45^{\circ}\)

A car moving over a straight path covers a distance \(\mathrm{x}\) with constant speed \(10 \mathrm{~ms}^{-1}\) and then the same distance with constant speed of \(\mathrm{V}_{2}\). If average speed of the car is \(16 \mathrm{~ms}^{-1}\), then \(\mathrm{V}_{2}=\ldots\) (A) \(30 \mathrm{~ms}^{-1}\) (B) \(20 \mathrm{~ms}^{-1}\) (C) \(40 \mathrm{~ms}^{-1}\) (D) \(25 \mathrm{~ms}^{-1}\)

A body starts its motion with zero velocity and its acceleration is $\left(3 \mathrm{~m} / \mathrm{s}^{2}\right)$. Find the distance travelled by it in fifth second. (A) \(15.5 \mathrm{~m}\) (B) \(17.5 \mathrm{~m}\) (C) \(13.5 \mathrm{~m}\) (D) \(14.5 \mathrm{~m}\)

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free