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Chapter 21: Problem 2761

What is the least count of the vernier calipers? (A) Smallest division on the vernier scale. (B) difference of the smallest division on the main scale and the smallest division on the vernier scale. (C) sum of the smallest division on the main scale and the smallest division on the vernier scale. (D) smallest division on the main scale.

Short Answer

Expert verified
The least count of vernier calipers is the difference between the smallest division on the main scale and the smallest division on the vernier scale. Therefore, the correct answer is (B).

Step by step solution

01

Understanding the scales of Vernier Calipers

Vernier calipers have two scales: the main scale and the vernier scale. The main scale is divided into millimeters while the vernier scale is fine-tuned to allow even more precise measurements.
02

Identifying the smallest division on both scales

The smallest division on the main scale is the smallest distance between two marks on the main scale, which usually represents 1mm. The smallest division on the vernier scale is the smallest distance between two marks on the vernier scale, and it is smaller than the smallest division on the main scale.
03

Determining the least count

The least count is the difference between the smallest division on the main scale and the smallest division on the vernier scale. This value represents the smallest length that can be accurately measured by the vernier calipers. So, the correct answer is: (B) Difference of the smallest division on the main scale and the smallest division on the vernier scale.

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Most popular questions from this chapter

What is the least count of commonly available vernier? (A) \(0.01 \mathrm{~cm}\) (B) \(0.001 \mathrm{~cm}\) (C) \(0.0001 \mathrm{~cm}\) (D) \(0.1 \mathrm{~cm}\)

When the zero mark on the vernier scale lies towards the left side of the zero mark of the main scale, when the jaws are connect, then what will be the zero error? (A) zero error is positive (B) zero error is negative (C) zero correction is positive (D) zero error does not exist

The edge of a cube is measured using a vernier caliper \((9\) divisions of the main scale is equal to 10 divisions of vernier scale and 1 main scale division is \(1 \mathrm{~mm}\) ). The main scale division reading is 10 and 1 division of vernier scale was found to be coinciding with the main scale. The mass of the cube is \(2.736 \mathrm{~g}\). What will be the density in $\left\\{\mathrm{g} /\left(\mathrm{cm}^{3}\right)\right\\}$ upto correct significant figures? (A) $2.66 \times 10^{-3}\left\\{\mathrm{~g} /\left(\mathrm{cm}^{3}\right)\right\\}$ (B) $2.66 \times 10^{3}\left\\{\mathrm{~g} /\left(\mathrm{cm}^{3}\right)\right\\}$ (C) \(2.66\left\\{\mathrm{~g} /\left(\mathrm{cm}^{3}\right)\right\\}\) (D) $2.66 \times 10^{-6}\left\\{\mathrm{~g} /\left(\mathrm{cm}^{3}\right)\right\\}$

In an unusual vernier, 9 vernier scale divisions coincide with 8 main scale division, then what is the least count of the vernier? (A) \((8 / 9) \mathrm{mm}\) (B) \((1 / 9) \mathrm{mm}\) (C) \((1 / 17) \mathrm{mm}\) (D) \((1 / 8) \mathrm{mm}\)

When the jaws of a standard vernier are together, the \(6^{\text {th }}\) main scale division coincides with the \(7^{\text {th }}\) vernier scale division, then what is the zero error? (A) \(-0.7 \mathrm{~mm}\) (B) \(+0.3 \mathrm{~mm}\) (C) \(-0.3 \mathrm{~mm}\) (D) \(+0.7 \mathrm{~mm}\)
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