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Chapter 21: Problem 2762

What is the least count of commonly available vernier? (A) \(0.01 \mathrm{~cm}\) (B) \(0.001 \mathrm{~cm}\) (C) \(0.0001 \mathrm{~cm}\) (D) \(0.1 \mathrm{~cm}\)

Short Answer

Expert verified
The least count of a commonly available vernier is (A) \(0.01 \,cm\).

Step by step solution

01

Recognize the information given

In this problem, we are given four choices for the least count of a commonly available vernier. We need to find the correct one by knowing the actual least count of the vernier scale.
02

Calculate the least count of the vernier scale

To find the least count, we need to know the difference between the main scale and the vernier scale. The least count of the vernier scale can be calculated using the formula: \(Least \, Count = \frac{1 \, MSD}{10}\) where MSD is the least count of the main scale, which is usually 1 mm or 0.1 cm.
03

Compare the calculated least count with the given choices

Using the formula from Step 2, we can calculate the least count: \(Least \, Count = \frac{1 \, MSD}{10} = \frac{0.1 \, cm}{10} = 0.01 \, cm\)
04

Choose the correct answer

By comparing the calculated least count with the given choices, we can see that the correct answer is: (A) \(0.01 \,cm\).

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Most popular questions from this chapter

If observed reading is OR, corrected reading is CR, zero error in \(\mathrm{ZE}\) and zero correction in \(\mathrm{ZC}\), then what will be the possibility? (A) \(\mathrm{CR}=\mathrm{OR}+\mathrm{ZC}\) and \(\mathrm{ZE}=\mathrm{CR}-\mathrm{OR}\) (B) \(\mathrm{CR}=\mathrm{OR}+\mathrm{ZE}\) and \(\mathrm{ZC}=\mathrm{CR}-\mathrm{OR}\) (C) \(\mathrm{CR}=\mathrm{OR}-\mathrm{ZC}\) and \(\mathrm{ZE}=\mathrm{OR}-\mathrm{CR}\) (D) \(\mathrm{CR}=\mathrm{OR}-\mathrm{ZE}\) and \(\mathrm{ZC}=\mathrm{CR}-\mathrm{OR}\)

In an unusual vernier, 9 vernier scale divisions coincide with 8 main scale division, then what is the least count of the vernier? (A) \((8 / 9) \mathrm{mm}\) (B) \((1 / 9) \mathrm{mm}\) (C) \((1 / 17) \mathrm{mm}\) (D) \((1 / 8) \mathrm{mm}\)

N divisions on the main scale of a vernier calipers coin sides with \((\mathrm{N}+1)\) divisions on the vernier scale. If each division on the main scale is of a units, the least of count of instrument is................ (A) \(\\{\mathrm{a} /(\mathrm{N}+1)\\}\) (B) \(\\{\mathrm{a} /(\mathrm{N}-1)\\}\) (C) \(\\{(N+1) / a\\}\) (D) \(\\{(N-1) / a\\}\)

When the zero mark on the vernier scale lies towards the right side of the zero mark of the main scale, when the jaws are in contact, then what will be the zero error? (A) zero correction in positive (B) zero correction is negative (C) zero error in positive (D) zero error does not exist

In an usual vernier, 10 vernier scale divisions, coin side with 8 main scale divisions, then what is the least count of the vernier? (A) \(0.1 \mathrm{~mm}\) (B) \(0.2 \mathrm{~mm}\) (C) \(0.8 \mathrm{~mm}\) (D) \((1 / 8) \mathrm{mm}\)
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