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Chapter 21: Problem 2763

When the zero mark on the vernier scale lies towards the left side of the zero mark of the main scale, when the jaws are connect, then what will be the zero error? (A) zero error is positive (B) zero error is negative (C) zero correction is positive (D) zero error does not exist

Short Answer

Expert verified
(B) zero error is negative

Step by step solution

01

Understand the Concept of Zero Error

Zero error occurs when the reading on the vernier caliper is not exactly zero when the jaws are completely closed. The zero error can be positive or negative depending on the position of the zero mark on the vernier scale relative to the zero mark on the main scale.
02

Analyze the Situation

In the given scenario, the zero mark on the vernier scale lies towards the left side of the zero mark of the main scale when the jaws are closed. This means that the vernier scale's zero mark is on the left side of the main scale's zero mark.
03

Determine the Zero Error

Since the zero mark of the vernier scale lies on the left side of the main scale's zero mark, the reading is smaller than it should be when the jaws are closed, resulting in a negative zero error. Thus, the correct answer is: (B) zero error is negative

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Most popular questions from this chapter

What is the least count of commonly available vernier? (A) \(0.01 \mathrm{~cm}\) (B) \(0.001 \mathrm{~cm}\) (C) \(0.0001 \mathrm{~cm}\) (D) \(0.1 \mathrm{~cm}\)

In an unusual vernier, 9 vernier scale divisions coincide with 8 main scale division, then what is the least count of the vernier? (A) \((8 / 9) \mathrm{mm}\) (B) \((1 / 9) \mathrm{mm}\) (C) \((1 / 17) \mathrm{mm}\) (D) \((1 / 8) \mathrm{mm}\)

When the zero mark on the vernier scale lies towards the right side of the zero mark of the main scale, when the jaws are in contact, then what will be the zero error? (A) zero correction in positive (B) zero correction is negative (C) zero error in positive (D) zero error does not exist

The edge of a cube is measured using a vernier caliper \((9\) divisions of the main scale is equal to 10 divisions of vernier scale and 1 main scale division is \(1 \mathrm{~mm}\) ). The main scale division reading is 10 and 1 division of vernier scale was found to be coinciding with the main scale. The mass of the cube is \(2.736 \mathrm{~g}\). What will be the density in $\left\\{\mathrm{g} /\left(\mathrm{cm}^{3}\right)\right\\}$ upto correct significant figures? (A) $2.66 \times 10^{-3}\left\\{\mathrm{~g} /\left(\mathrm{cm}^{3}\right)\right\\}$ (B) $2.66 \times 10^{3}\left\\{\mathrm{~g} /\left(\mathrm{cm}^{3}\right)\right\\}$ (C) \(2.66\left\\{\mathrm{~g} /\left(\mathrm{cm}^{3}\right)\right\\}\) (D) $2.66 \times 10^{-6}\left\\{\mathrm{~g} /\left(\mathrm{cm}^{3}\right)\right\\}$

When the jaws of a standard vernier are together, the \(6^{\text {th }}\) main scale division coincides with the \(7^{\text {th }}\) vernier scale division, then what is the zero error? (A) \(-0.7 \mathrm{~mm}\) (B) \(+0.3 \mathrm{~mm}\) (C) \(-0.3 \mathrm{~mm}\) (D) \(+0.7 \mathrm{~mm}\)
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