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Chapter 27: Problem 2817

The terminal velocity of fall of lead shots in the cylindrical vessel is influenced by the nearness of the walls of the vessel. Hence the velocity in formula is divided by a factor \([1+\\{(2.4 r) / R\\}] .\) Where \(r\) is the radius of the lead shots and \(\mathrm{R}\) the radius of the vessel. This is called.......... (A) Ladenburg correction (B) Velocity correction (C) End-correction (D) Rydberg correction

Short Answer

Expert verified
The correction factor in the terminal velocity formula, \(\frac{1}{1+\{(2.4r)/R\}}\), is called the (A) Ladenburg correction.

Step by step solution

01

Option A: Ladenburg Correction

The Ladenburg correction, which is often applied in the context of fluid mechanics or terminal velocity experiments, accounts for the influence of the wall of the cylindrical vessel on the terminal velocity of particles. Therefore, it seems like a good fit to describe the given correction factor in the terminal velocity formula.
02

Option B: Velocity Correction

Velocity correction, in general, refers to any modification of the velocity in a certain situation. In this case, the given correction factor is specific to the terminal velocity of lead shots in a cylindrical vessel. While the term "velocity correction" could be applied broadly to any scenario that requires adjusting velocity, it does not specifically relate to the given correction factor.
03

Option C: End-correction

End-correction, typically used in the context of acoustics or wave propagation, is a correction factor added to compensate for the effect of the end of a tube or pipe on the resonant frequency of an emitted sound. This correction does not seem to have any relevance to the given terminal velocity correction factor in this exercise.
04

Option D: Rydberg Correction

The Rydberg correction refers to a modification in atomic spectroscopy based on the Rydberg formula, which estimates the energy levels and frequencies of spectral lines. This correction is not related to the terminal velocity of particles or fluid mechanics, and therefore, it does not describe the given correction factor. Based on these definitions, it is clear that the correct term for the given terminal velocity correction factor is: (A) Ladenburg correction

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Most popular questions from this chapter

A steel ball of diameter \(3.2 \mathrm{~mm}\) falls under gravity through an oil of density \(920 \mathrm{~kg} \mathrm{~m}^{-3}\) and viscosity $1.64 \mathrm{Ns} \mathrm{m}^{-2}\(. The density of steel. may be taken as \)7820 \mathrm{~kg} \mathrm{~m}^{-3}$. What is the terminal velocity of the ball ? (A) \(3.45 \mathrm{cms}^{-1}\) (B) \(4.25 \mathrm{cms}^{-1}\) (C) \(1.85 \mathrm{~cm}^{-1}\) (D) \(2.39 \mathrm{cms}^{-1}\)

The velocity of a small ball of mass \(\mathrm{m}\) and density \(\mathrm{d}_{1}\) when dropped in a container filled with glycerine becomes constants after sometime. What is the viscous force acting on the ball ? (density of glycerine is \(\mathrm{d}_{2}\) ) (A) \(m g\left\\{1-\left(d_{1} / d_{2}\right)\right\\}\) (B) \(m g\left\\{1-\left(d_{2} / d_{1}\right)\right\\}\) (C) \(m g\left\\{d_{1} /\left(d_{1}-d_{2}\right)\right\\}\) (D) $\operatorname{mg}\left\\{\mathrm{d}_{2} /\left(\mathrm{d}_{1}-\mathrm{d}_{2}\right)\right\\}$

64 equal drops of water are falling through air with a steady velocity \(\mathrm{V}_{0}\), if the drops coalesce, what is their new velocity? (A) \(4 \mathrm{~V}_{0}\) (B) \(2^{\\{(-1) / 3\\}} \mathrm{V}_{0}\) (C) \(2 \mathrm{~V}_{0}\) (D) \(2^{(1 / 3)} \mathrm{V}_{0}\)

The C.G.S. unit of coefficient of viscosity is poise and the SI unit is \(\mathrm{Pa}-\mathrm{S}\). What is the relation between the two ? (A) \(1 \mathrm{~Pa}-\mathrm{s}=10^{3}\) poise (B) \(1 \mathrm{~Pa}-\mathrm{s}=10^{4}\) poise (C) \(1 \mathrm{~Pa}-\mathrm{s}=10\) poise (D) \(1 \mathrm{~Pa}-\mathrm{s}=100\) poise

A steel ball of diameter \(3 \mathrm{~mm}\) falls through glycerine and covers a distance of \(25 \mathrm{~cm}\) in \(10 \mathrm{~S} .\) The specific gravity of steel and glycerine are \(7.8\) and \(1.26\) respectively. The viscosity of glycerine is about........ pascal-sec (A) \(1.3\) (B) \(1.5\) (C) \(0.8\) (D) \(1.0\)
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