Chapter 3: Problem 341
A cold soft drink is kept on the balance. When the cap is open, then the weight (A) Increases (B) Decreases (C) First increase then decreases (D) Remains same
Chapter 3: Problem 341
A cold soft drink is kept on the balance. When the cap is open, then the weight (A) Increases (B) Decreases (C) First increase then decreases (D) Remains same
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Get started for freeAn object of mass \(3 \mathrm{~kg}\) is moving with a velocity of $5 \mathrm{~m} / \mathrm{s}\( along a straight path. If a force of \)12 \mathrm{~N}$ is applied for \(3 \mathrm{sec}\) on the object in a perpendicular to its direction of motion. The magnitude of velocity of the particle at the end of $3 \mathrm{sec}\( is \)\mathrm{m} / \mathrm{s}$. (A) (B) 12 (C) 13 (D) 4
A sparrow flying in air sits on a stretched telegraph wire. If the weight of the sparrow is \(\mathrm{W}\), which of the following is true about the tension T produced in the wire? (A) \(\mathrm{T}=\mathrm{W}\) (B) \(\mathrm{T}<\mathrm{W}\) (C) \(\mathrm{T}=0\) (D) \(\mathrm{T}>\mathrm{W}\)
A force of \(8 \mathrm{~N}\) acts on an object of mass \(5 \mathrm{~kg}\) in \(\mathrm{X}\) -direction and another force of \(6 \mathrm{~N}\) acts on it in \(\mathrm{Y}\) -direction. Hence, the magnitude of acceleration of object will be (A) \(1.5 \mathrm{~ms}^{-2}\) (B) \(2.0 \mathrm{~ms}^{-2}\) (C) \(2.5 \mathrm{~ms}^{-2}\) (D) \(3.5 \mathrm{~ms}^{-2}\)
A rope which can withstand a maximum tension of \(400 \mathrm{~N}\) hangs from a tree. If a monkey of mass \(30 \mathrm{~kg}\) climbs on the rope in which of the following cases-will the rope break? (take \(g=10 \mathrm{~ms}^{-}{ }^{2}\) and neglect the mass of rope \()\) (A) When the monkey climbs with constant speed of \(5 \mathrm{~ms}^{-1}\) (B) When the monkey climbs with constant acceleration of \(2 \mathrm{~ms}^{-2}\) (C) When the monkey climbs with constant acceleration of \(5 \mathrm{~ms}^{-2}\) (D) When the monkey climbs with the constant speed of \(12 \mathrm{~ms}^{-1}\)
The upper half of an inclined plane of inclination \(\theta\) is perfectly smooth while the lower half is rough A body starting from the rest at top come back to rest at the bottom, then the coefficient of friction for the lower half is given by (A) \(\mu=\sin \theta\) (B) \(\mu=\cot \theta\) (C) \(\mu=2 \cos \theta\) (D) \(\mu=2 \tan \theta\)
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