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Chapter 3: Problem 363

Newton's third law of motion leads to the law of conservation of (A) Angular momentum (B) Energy (C) mass (D) momentum

Short Answer

Expert verified
The correct answer is (D) momentum. The conservation of momentum is a direct consequence of Newton's third law of motion, as the equal and opposite forces between two interacting objects leads to equal and opposite changes in their momentum, thus conserving total momentum in a closed system.

Step by step solution

01

Option A: Angular momentum

Newton's third law of motion is primarily concerned with linear forces acting upon objects. While angular momentum can be conserved in certain scenarios, it is not a direct consequence of Newton's third law. This option is incorrect.
02

Option B: Energy

Conservation of energy refers to the principle that both kinetic and potential energy in a closed system remains constant. While energy conservation is an essential principle in physics, it is not a direct result of Newton's third law of motion. So this option is incorrect.
03

Option C: Mass

Conservation of mass refers to the principle that the total mass of substances in a closed system remains constant. While it is a fundamental concept in chemistry and thermodynamics, it is not a direct outcome of Newton's third law of motion. This option is incorrect.
04

Option D: Momentum

Momentum is the product of mass and velocity. According to Newton's third law, the forces between two objects are equal and opposite; therefore, when the objects interact with each other, their momentum change is also equal and opposite. This leads to the conservation of total momentum in a closed system of interacting objects. So the consequence of Newton's third law of motion is the conservation of momentum. Thus, the correct answer is (D) momentum.

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Most popular questions from this chapter

An impulsive force of \(100 \mathrm{~N}\) acts on a body for \(1 \mathrm{sec}\) What is the change in its linear momentum ? (A) \(10 \mathrm{~N}-\mathrm{S}\) (B) \(100 \mathrm{~N}-\mathrm{S}\) (C) \(1000 \mathrm{~N}-\mathrm{S}\) (D) \(1 \mathrm{~N}-\mathrm{S}\)

Same forces act on two bodies of different mass \(2 \mathrm{~kg}\) and $5 \mathrm{~kg}$ initially at rest. The ratio of times required to acquire same final velocity is (A) \(5: 3\) (B) \(25: 4\) (C) \(4: 25\) (D) \(2: 5\)

Three Forces \(F_{1}, F_{2}\), and \(F_{3}\) together keep a body in equilibrium. If \(F_{1}=3 \mathrm{~N}\) along the positive \(\mathrm{X}\) - axis, \(\mathrm{F}_{2}=4 \mathrm{~N}\) along the positive Y-axis then the third force \(F_{3}\) is (A) \(5 \mathrm{~N}\) -making an angle \(\theta=\tan ^{-1}(3 / 4)\) with negative \(\mathrm{y}\) -axis (B) \(5 \mathrm{~N}\) -making an angle \(\theta=\tan ^{-1}(4 / 3)\) with negative \(\mathrm{y}\) -axis (C) \(7 \mathrm{~N}\) -making an angle \(\theta=\tan ^{-1}(3 / 4)\) with negative \(\mathrm{y}\) -axis (D) \(7 \mathrm{~N}\) -making an angle \(\theta=\tan ^{-1}(4 / 3)\) with negative \(\mathrm{y}\) -axis

Same force acts on two bodies of different masses \(2 \mathrm{~kg}\) and $4 \mathrm{~kg}$ initially at rest. the ratio of times required to acquire same final velocity is (A) \(2: 1\) (B) \(1: 2\) (C) \(1: 1\) (D) \(4: 16\)

A player caught a cricket ball of mass \(150 \mathrm{~g}\) moving at the rate of \(20 \mathrm{~ms}^{-1}\). If the catching process be completed in $0.1 \mathrm{~s}$ the force of the blow exerted by the ball on the hands of player is (A) \(0.3 \mathrm{~N}\) (B) \(30 \mathrm{~N}\) (C) \(300 \mathrm{~N}\) (D) \(3000 \mathrm{~N}\)
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