What is the unit of temperature coefficient of resistance? (A) \(\Omega^{-1}{ }^{\circ} \mathrm{C}\) (B) \(\Omega^{1}{ }^{\circ} \mathrm{C}^{-1}\) (C) \({ }^{\circ} \mathrm{C}^{-1}\) (D) \(\Omega^{0}{ }^{\circ} \mathrm{C}^{-1}\)

Short Answer

Expert verified
(B) \(\Omega^{1}{ }^{\circ} \mathrm{C}^{-1}\)

Step by step solution

01

Option A: \(\Omega^{-1}{ }^{\circ} \mathrm{C}\)

This option has the inverse of ohms multiplied by degrees Celsius. This does not represent a ratio between resistance and temperature, so this option is incorrect.
02

Option B: \(\Omega^{1}{ }^{\circ} \mathrm{C}^{-1}\)

This option has ohms divided by the inverse of degrees Celsius. This represents a ratio between resistance and temperature, so this option is correct.
03

Option C: \({ }^{\circ} \mathrm{C}^{-1}\)

This option only has the inverse of degrees Celsius, without any unit of resistance. It doesn't represent a ratio between resistance and temperature, so this option is incorrect.
04

Option D: \(\Omega^{0}{ }^{\circ} \mathrm{C}^{-1}\)

This option results in ohms raised to the power of zero, which simplifies to 1. So we are left with the inverse of degrees Celsius, and there is no unit of resistance present. This doesn't represent a ratio between resistance and temperature, so this option is incorrect. After our analysis, the correct unit for the temperature coefficient of resistance is:
05

Answer:

(B) \(\Omega^{1}{ }^{\circ} \mathrm{C}^{-1}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What is the resistance of an open key? (A) \(\infty\) (B) Can't be determined (C) 0 (D) depends on the other resistance in the circuit

A wire is in the form of a tetrahedron shown in figure. The resistance of each wire is \(\mathrm{R}\). What is the resistance of the frame between the corners \(\mathrm{A}\) and \(\mathrm{B}\). (A) \((2 \mathrm{R} / 3)\) (B) \(2 \mathrm{R}\) (C) \(\mathrm{R}\) (D) \((\mathrm{R} / 2)\)

In a simple meter-bridge circuit, the both gaps are bridge by coils \(\mathrm{P}\) and \(\mathrm{Q}\) having the smaller resistance. A balance is obtained when the jockey key makes contact at a point of the bridge wire $40 \mathrm{~cm}\( from the \)\mathrm{P}\( end. On shunting the coil \)\mathrm{Q}$ with a resistance of \(50 \Omega\) the balance point is moved through $10 \mathrm{~cm}\(. What are the resistance of \)\mathrm{P}\( and \)\mathrm{Q}$ ? (A) \([(100) / 3] \Omega,[(100) / 2] \Omega\) respectively (B) \([(50) / 3] \Omega,[(50) / 2] \Omega\) respectively (C) \([(25) / 3] \Omega,[(25) / 2] \Omega\) respectively (D) \([(75) / 3] \Omega,[(75) / 2] \Omega\) respectively

In meter bridge experiment, A thin uniform wire \(\mathrm{AB}\) of length $1 \mathrm{~m}\( and unknown resistance \)\mathrm{x}\( and a resistance of \)12 \Omega$ are connected. In the above question, after appropriate conditions are made, it is found that no deflection takes places in the galvanometer when the sliding jockey touches the wire at a distance of \(60 \mathrm{~cm}\) from \(\mathrm{A}\). What is the value of the resistance \(\mathrm{X}\) ? (A) \(18 \Omega\) (B) \(8 \Omega\) (C) \(16 \Omega\) (D) \(4 \Omega\)

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free