Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 34: Problem 2876

An ammeter of range \(5 \mathrm{~A}\) is to be converted into an voltmer of range \(10 \mathrm{~V}\). If the resistance of ammeter be \(0.1\), then what resistance should be connected in series with it ? (A) \(4.9 \Omega\) (B) \(2.1 \Omega\) (C) \(1.1 \Omega\) (D) \(1.9 \Omega\)

Short Answer

Expert verified
The resistance that should be connected in series with the ammeter to convert it into a voltmeter of range 10V is \(1.9 \Omega\). The correct answer is (D).

Step by step solution

01

Find the internal resistance of the ammeter

It is given that the resistance of the ammeter is 0.1 Ω. Let's denote this internal resistance as R_a. So, R_a = 0.1 Ω
02

Find the current flowing through the ammeter

The maximum current that the ammeter can measure is 5 A. It is given in the problem and we will denote it as I. So, I = 5 A
03

Calculate the current through the voltmeter

We need to convert the ammeter into a voltmeter with a range of 10 V. Let's denote this voltage range as V. So, V = 10 V Now, use the Ohm's Law to find the current through the voltmeter (I_v). I_v = V / (R_a + R)
04

Calculate the resistance required in series

In this step, we will calculate the resistance (R) that should be connected in series with the ammeter to convert it into a voltmeter. From Step 3, we have the relation: I_v = V / (R_a + R) We know that I_v = I, V = 10 V, and R_a = 0.1 Ω. Substitute these values in the equation and solve for R. I = 10 / (0.1 + R) 5 = 10 / (0.1 + R) Rearrange the equation and solve for R: R = (10 / 5) - 0.1 = 2 - 0.1 = 1.9 Ω So, the resistance that should be connected in series with the ammeter is 1.9 Ω. The correct answer is (D).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

One micro-ammeter has a resistance of \(100 \Omega\) and a full scale range of \(50 \mu \mathrm{A}\). ft can be used as a voltmeter or as a higher range ammeter provided a resistance is added to it. Pick the correct range and resistance combinations (s). (A) \(5 \mathrm{~mA}\) range with \(1 \Omega\) resistance in parallel (B) \(10 \mathrm{~mA}\) range with \(1 \Omega\) resistance in parallel (C) \(10 \mathrm{~V}\) range with \(200 \mathrm{k} \Omega\) resistance in series (D) \(50 \mathrm{~V}\) range with \(10 \mathrm{k} \Omega\) resistance in series

The range of a galvanometer of resistance \(\mathrm{G}\) ohm is \(\mathrm{V}\) volt. The resistance required to be connected in series with it in order to convert it into voltmeter of range \(\mathrm{nV}\) volt will be (A) (G/n) (B) \(\mathrm{nG}\) (C) \((\mathrm{n}-1) \mathrm{G}\) (D) \([\mathrm{G} /(\mathrm{n}-1)]\)

A galvanometer, having a resistance of \(50 \Omega\), gives a full scale deflection for a current of \(0.05 \mathrm{~A}\). The length in meter of a resistance wire of area of cross-section \(2.97 \times 10^{2} \mathrm{~cm}^{2}\) that can be used to convert the galvanometer into an ammeter which can read a maximum of \(5 \mathrm{~A}\) current is (specific resistance of wire $=5 \times 10^{-7} \Omega \mathrm{m}$ ) (A) \(1.5\) (B) 6 (C) 8 (D) 3

What is the relation between figure of merit \((\mathrm{k})\) and current sensitivity \(\left(\mathrm{S}_{1}\right) ?\) (A) \(\mathrm{S}_{1}=\mathrm{k}^{-1}\) (B) \(\mathrm{S}_{1}=(\mathrm{k} / 2)\) (C) \(\mathrm{S}_{1}=\mathrm{kV}\) (D) \(\mathrm{S}_{1}=(\mathrm{k}) \mathrm{I}\)

The seave of a galvanometer of resistance \(100 \mathrm{Q}\) contains 25 divisions. It gives a deflection of 1 division on passing a current of $4 \times 10^{-4} \mathrm{~A}$. The resistance in ohm to be added to it. so that it may become a voltmeter of range \(2.5 \mathrm{~V}\) is (A) 250 (B) 300 (C) 150 (D) 100
See all solutions

Recommended explanations on English Textbooks

Language Acquisition

Read Explanation

Summary Text

Read Explanation

Lexis and Semantics

Read Explanation

Graphology

Read Explanation

Essay Plan

Read Explanation

5 Paragraph Essay

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free