A vessel of depth \(\mathrm{t}\) is half filled with oil of refractive index \(\mathrm{n}_{1}\) and the other half is filled with water (refractive index \(\mathrm{n}_{2}\) ). The apparent depth of the vessel when viewed from above is \(\ldots \ldots\) (A) $\left[\left\\{2 t\left(n_{1}-\mathrm{n}_{2}\right)\right\\} /\left(\mathrm{n}_{1} \mathrm{n}_{2}\right)\right]$ (B) $\left[\left\\{2 \mathrm{t}\left(\mathrm{n}_{1}+\mathrm{n}_{2}\right)\right\\} /\left(\mathrm{n}_{1} \mathrm{n}_{2}\right)\right]$ (C) $\left[\left\\{t\left(n_{1}-n_{2}\right)\right\\} /\left(2 n_{1} \mathrm{n}_{2}\right)\right]$ (D) $\left[\left\\{t\left(n_{1}+n_{2}\right)\right\\} /\left(2 n_{1} \mathrm{n}_{2}\right)\right]$

Short Answer

Expert verified
The apparent depth of the vessel when viewed from above is \(\boxed{\text{(D)}\ \left[\frac{t\left(n_{1}+n_{2}\right)}{2 n_{1}n_{2}}\right]} \).

Step by step solution

01

Calculate the actual depths of oil and water

As the vessel is half-filled with oil and half-filled with water, the actual depths of oil and water in the vessel can be calculated as follows: Actual depth of oil: \(t_{1} = \frac{t}{2}\) Actual depth of water: \(t_{2} = \frac{t}{2}\)
02

Calculate apparent depths of oil and water

The formula for calculating the apparent depth, given the actual depth and refractive index, is: Apparent depth = \(\frac{\text{Actual Depth}}{\text{Refractive Index}}\) Using this formula, we'll calculate the apparent depths of oil and water: For oil: Apparent depth \(p_{1} = \frac{t_{1}}{n_{1}} = \frac{\frac{t}{2}}{n_{1}}\) For water: Apparent depth \(p_{2} = \frac{t_{2}}{n_{2}} = \frac{\frac{t}{2}}{n_{2}}\)
03

Calculate the total apparent depth of the vessel

To find the total apparent depth of the vessel, we will add up the apparent depths of oil and water: Total apparent depth \(p_{t} = p_{1} + p_{2}\) Plugging in the values we found in Step 2: \(p_{t} = \frac{\frac{t}{2}}{n_{1}} + \frac{\frac{t}{2}}{n_{2}}\) By finding a common denominator, we can simplify this expression further: \(p_{t} = \frac{t(n_{1} + n_{2})}{2n_{1}n_{2}}\) Comparing this expression with the given options, we find that the apparent depth of the vessel when viewed from above is: \[\boxed{\text{(D)}\ \left[\frac{t\left(n_{1}+n_{2}\right)}{2 n_{1}n_{2}}\right]} \]

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Most popular questions from this chapter

A plane mirror is placed at the bottom of a tank containing a liquid of refractive index \(\mathrm{n} . \mathrm{P}\) is a small object at a height \(\mathrm{h}\) above the mirror. An observer O, vertically above P, outside the liquid sees \(\mathrm{P}\) and its image in the mirror. The apparent distance between these two will be. (A) \((2 \mathrm{~h} / \mathrm{n})\) (B) \(2 \mathrm{~h}(\mathrm{n}-1)\) (C) \(h[1+(1 / n)]\) (D) \((2 \mathrm{n} / \mathrm{h})\)

A beam of light is converging towards a point I on a screen. A plane parallel plate of glass whose thickness is in the direction of beam \(=\mathrm{t}\), refractive index \(=\mathrm{n}\) is introduced in the path of the beam. The convergence point is shifted by \(\ldots \ldots\) (A) \(t[1+(1 / n)]\) never (B) \(t[1-(1 / n)]\) nearer (C) \(\mathrm{t}[1+(1 / \mathrm{n})]\) away (D) \(t[1-(1 / n)]\) away

Light travels through a glass plate of thickness \(t\) and having refractive index \(\mathrm{n}\). If \(\mathrm{C}\) be the velocity of light in vacuum. What is the time taken by the light of travel this thickness of glass? (A) \(\left(\mathrm{t}_{\mathrm{C}} / \mathrm{n}\right)\) (B) \(\operatorname{tn} \mathrm{C}\) (C) (nt / C) (D) \((\mathrm{t} / \mathrm{n} \mathrm{C})\)

A bird in air looks at a fish vertically below it and inside water, \(h_{1}\) is the height of the bird above the surface of water and \(\mathrm{h}_{2}\), the depth of the fish below the surface of water. If refractive index of water with respect to air be \(\mathrm{n}\), then what is the distance of the fish observed by the bird? (A) \(\mathrm{n}_{1} \mathrm{~h}_{1}+\mathrm{nh}_{2}\) (B) \(\mathrm{nh}_{1}+\mathrm{h}_{2}\) (C) \(\mathrm{h}_{1}+\left(\mathrm{h}_{2} / \mathrm{n}\right)\) (D) \(\mathrm{h}_{1}+\mathrm{h}_{2}\)

The velocity of light in glass whose refractive index with respect to air is \(1.5\) is \(2 \times 10^{8} \mathrm{~m} / \mathrm{s}\). In a certain liquid, the velocity of light is found to be \(2.5 \times 10^{8} \mathrm{~m} / \mathrm{s}\). What is the refractive index of the liquid with respect to air? (A) \(1.44\) (B) \(0.80\) (C) \(1.20\) (D) \(0.64\)

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