Chapter 38: Problem 2916
In a semiconductor diode, barrier potential offers opposition to only (A) free electrons in \(\mathrm{N}\) region (B) holes in the P region (C) minority carriers in both regions (D) majority carriers in both regions.
Chapter 38: Problem 2916
In a semiconductor diode, barrier potential offers opposition to only (A) free electrons in \(\mathrm{N}\) region (B) holes in the P region (C) minority carriers in both regions (D) majority carriers in both regions.
All the tools & learning materials you need for study success - in one app.
Get started for freeWhen \(\mathrm{P}-\mathrm{N}\) junction diode is forward based, then (A) Both the depletion region and barrier height are reduced. (B) Both depletion region and barrier height are increased. (C) The deflection region is winded and barrier height is reduced. (D) The depletion region is reduced and barrier height is increased.
The electrical resistance of depletion layer is large because (A) it contains electrons as charge carriers (B) it has holes as charge carriers. (C) it has no charge carriers. (D) It has large number of charge carriers
When P-N junction diode is in forward biased condition, the flow of current is mainly due to (A) both by drift and diffusion of electrons (B) the drift of electrons (C) the diffusion of electrons (D) none of the a above
A P-N junction is said to be forward based when (A) a magnetic field is applied in the region of junction. (B) a potential difference is applied across \(\mathrm{P}\) and \(\mathrm{N}\) regions making \(\mathrm{P}\) region negative and \(\mathrm{N}\) region positive. (C) not potential difference is applied across \(\mathrm{P}\) and \(\mathrm{N}\) regions. (D) a potential difference is applied across \(\mathrm{P}\) and \(\mathrm{N}\) regions making P region positive and N region negative.
The number of minority carriers crossing the junction of diode depends primarily on the (A) magnitude of potential barrier (B) magnitude of the forward bias barrier. (C) rate of thermal generation of electron hole pair. (D) concentration of doping impurities.
What do you think about this solution?
We value your feedback to improve our textbook solutions.