If a man increase his speed by \(2 \mathrm{~m} / \mathrm{s}\), his $\mathrm{K} . \mathrm{E}$. is doubled, the original speed of the man is (A) \((2+2 \sqrt{2}) \mathrm{m} / \mathrm{s}\) (B) \((2+\sqrt{2}) \mathrm{m} / \mathrm{s}\) (C) \(4 \mathrm{~m} / \mathrm{s}\) (D) \((1+2 \sqrt{2}) \mathrm{m} / \mathrm{s}\)

Short Answer

Expert verified
The original speed of the man is (B) \((2+\sqrt{2}) \mathrm{m} / \mathrm{s}\).

Step by step solution

01

Recall the formula for Kinetic Energy

Kinetic energy is given by the formula: \(K.E. = \frac{1}{2}mv^2\) where, \(K.E.\) = kinetic energy \(m\) = mass (which remains constant for the man) \(v\) = velocity (speed in this case)
02

Set up the equations

Let the original speed of the man be \(v\) m/s. Then, when the man increases his speed by 2 m/s, the new speed becomes \((v + 2)\) m/s. From the information given, we know that doubling the original kinetic energy is equal to the kinetic energy at the higher speed. So, we can write the equation: \(2 \cdot \frac{1}{2}m(v)^2 = \frac{1}{2}m(v + 2)^2\)
03

Simplify the equation

First, notice that the factors \(\frac{1}{2}m\) can be canceled from both sides: \(2v^2 = (v + 2)^2\) Now, expand and simplify the equation: \(2v^2 = v^2 + 4v + 4\) \(v^2 - 4v - 4 = 0\)
04

Solve the quadratic equation

Now, we must solve the quadratic equation for \(v\). Use the quadratic formula: \(v = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) For the equation \(v^2 - 4v - 4 = 0\), the values are: \(a = 1\) \(b = -4\) \(c = -4\) Plugging these values into the formula: \(v = \frac{4 \pm \sqrt{(-4)^2 - 4(1)(-4)}}{2 (1)}\)
05

Find the value of v

Now, calculate the value of \(v\): \(v = \frac{4 \pm \sqrt{16+16}}{2}\) \(v = \frac{4 \pm \sqrt{32}}{2}\) \(v = 2 \pm \frac{\sqrt{32}}{2}\) The possible values for the original speed are: \(v_1 = 2 + \frac{\sqrt{32}}{2}\) and \(v_2 = 2 - \frac{\sqrt{32}}{2}\) As speed cannot be negative, we can eliminate \(v_2\). Therefore, the original speed of the man is: \(v = 2 + \frac{\sqrt{32}}{2}\) Comparing with the given options, we see that the correct answer is: (B) \((2+\sqrt{2}) \mathrm{m} / \mathrm{s}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assertion and Reason are given in following questions. Each question have four option. One of them is correct it. (1) If both assertion and reason and the reason is the correct explanation of the Assertion. (2) If both assertion and reason are true but reason is not the correct explanation of the assertion. (3) If the assertion is true but reason is false. (4) If the assertion and reason both are false. Assertion: stopping distance \(=[\\{\) Kinetic energy \(\\} /\\{\) Stopping force \(\\}]\) Reason: Work done in stopping a body is equal to K.E. of the body. (A) 1 (B) 2 (C) 3 (D) 4

A spherical ball of mass \(15 \mathrm{~kg}\) stationary at the top of a hill of height \(82 \mathrm{~m} .\) It slides down a smooth surface to the ground, then climbs up another hill of height \(32 \mathrm{~m}\) and finally slides down to horizontal base at a height of \(10 \mathrm{~m}\) above the ground. The velocity attained by the ball is (A) \(30 \sqrt{10 \mathrm{~m} / \mathrm{s}}\) (B) \(10 \sqrt{30 \mathrm{~m} / \mathrm{s}}\) (C) \(12 \sqrt{10} \mathrm{~m} / \mathrm{s}\) (D) \(10 \sqrt{12} \mathrm{~m} / \mathrm{s}\)

Assertion and Reason are given in following questions. Each question have four option. One of them is correct it. (1) If both assertion and reason and the reason is the correct explanation of the Assertion. (2) If both assertion and reason are true but reason is not the correct explanation of the assertion. (3) If the assertion is true but reason is false. (4) If the assertion and reason both are false. Assertion: A weight lifter does no work in holding the weight up. Reason: Work done is zero because distance moved is zero. (A) 1 (B) 2 (C) 3 (D) 4

An engine pump is used to pump a liquid of density \(\rho\) continuously through a pipe of cross-sectional area \(\mathrm{A}\). If the speed of flow of the liquid in the pipe is \(\mathrm{v}\), then the rate at which kinetic energy is being imparted to the liquid is (A) \((1 / 2) \mathrm{A} \rho \mathrm{V}^{3}\) (B) \((1 / 2) \mathrm{A} \rho \mathrm{V}^{2}\) (C) \((1 / 2) \mathrm{A} \rho \mathrm{V}\) (B) \(\mathrm{ApV}\)

A ball of mass \(5 \mathrm{~kg}\) is striding on a plane with initial velocity of \(10 \mathrm{~m} / \mathrm{s}\). If co-efficient of friction between surface and ball is \((1 / 2)\), then before stopping it will describe \(\ldots \ldots\) \(\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)\) (A) \(12.5 \mathrm{~m}\) (B) \(5 \mathrm{~m}\) (C) \(7.5 \mathrm{~m}\) (D) \(10 \mathrm{~m}\)

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free