A nucleus at rest splits into two nuclear parts having same density and radii in the ratio \(1: 2\). Their velocities are in the ratio (A) \(2: 1\) (B) \(4: 1\) (C) \(6: 1\) (D) \(8: 1\)

Short Answer

Expert verified
The ratio of the velocities of the two parts after the nucleus splits is 8:1. This is determined using the conservation of momentum and the given ratio of radii and density. The ratio v1/v2 is calculated as \(8r^3/r^3\), resulting in a ratio of 8:1. So, the correct answer is (D) $8:1$.

Step by step solution

01

Identify the given information and the unknown variables

We are given that the nucleus splits into two parts of radii in the ratio 1:2. These parts have the same density, and we need to find the ratio of their velocities. Let the radii of the two parts be r and 2r, their densities be ρ, and their velocities be v1 and v2 respectively. Our aim is to find the ratio v1/v2.
02

Calculate the masses of the parts using density

The volume of a sphere is given by the formula: V = \(\frac{4}{3}\pi{r^3}\) For parts 1 and 2, we have: V1 = \(\frac{4}{3}\pi{r^3}\) and V2 = \(\frac{4}{3}\pi{(2r)^3}\) The mass of an object can be calculated using the formula: mass = density × volume Therefore, mass1 (m1) = ρ × V1 = ρ × \(\frac{4}{3}\pi{r^3}\) mass2 (m2) = ρ × V2 = ρ × \(\frac{4}{3}\pi{(2r)^3}\)
03

Apply the conservation of momentum

As the nucleus was initially at rest, the total initial momentum is zero. So, the total momentum of the two parts should also be equal to zero. This can be written mathematically as: m1 × v1 = m2 × v2 Substitute the masses of the parts (m1 and m2) calculated in step 2: (ρ × \(\frac{4}{3}\pi{r^3}\)) × v1 = (ρ × \(\frac{4}{3}\pi{(2r)^3}\)) × v2
04

Solve for the ratio of velocities v1/v2

We can cancel out the ρ and \(\frac{4}{3}\pi\) terms from both sides of the equation: \(r^3\) × v1 = \((2r)^3\) × v2 Now, group the terms of v1 and v2: \(\frac{v1}{v2}\) = \(\frac{(2r)^3}{r^3}\) \(\frac{v1}{v2}\) = \(\frac{8r^3}{r^3}\) \(\frac{v1}{v2}\) = \(8\) The ratio of velocities of the two parts is 8:1, therefore the correct answer is option (D).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A body having a mass of \(0.5 \mathrm{~kg}\) slips along the wall of a semispherical smooth surface of radius \(20 \mathrm{~cm}\) shown in figure. What is the velocity of body at the bottom of the surface $?\left(\mathrm{~g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)$ (A) \(2 \mathrm{~m} / \mathrm{s}\) (B) \(2 \mathrm{~m} / \mathrm{s}\) (C) \(2 \sqrt{2} \mathrm{~m} / \mathrm{s}\) (D) \(4 \mathrm{~m} / \mathrm{s}\)

A particle of mass \(0.5 \mathrm{~kg}\) travels in a straight line with velocity \(\mathrm{v}=\mathrm{ax}^{3 / 2}\), Where $\mathrm{a}=5 \mathrm{~m}^{[(-1) / 2]} \mathrm{s}^{-1}$. The work done by the net force during its displacement from \(\mathrm{x}=0\) to $\mathrm{x}=2 \mathrm{~m}$ is (A) \(50 \mathrm{~J}\) (B) \(45 \mathrm{~J}\) (C) \(25 \mathrm{~J}\) (D) None of these

An open knife edge of mass \(\mathrm{m}\) is dropped from a height \(\mathrm{h}\) on a wooden floor. If the blade penetrates up to the depth d into the wood, the average resistance offered by the wood to the knife edge is, (A) \(\mathrm{mg}\) (B) \(\mathrm{mg}(1+\\{\mathrm{h} / \mathrm{d}\\})\) (C) \(\mathrm{mg}(1+\\{\mathrm{h} / \mathrm{d}\\})^{2}\) (D) \(m g(1-\\{h / d\\})\)

The potential energy of a projectile at its highest point is (1/2) th the value of its initial kinetic energy. Therefore its angle of projection is (A) \(30^{\circ}\) (B) \(45^{\circ}\) (C) \(60^{\circ}\) (D) \(75^{\circ}\)

Three objects \(\mathrm{A}, \mathrm{B}\) and \(\mathrm{C}\) are kept in a straight line on a frictionless horizontal surface. These have masses $\mathrm{m}, 2 \mathrm{~m}\( and \)\mathrm{m}\( respectively. The object \)\mathrm{A}$ moves towards \(\mathrm{B}\) with a speed \(9 \mathrm{~m} / \mathrm{s}\) and makes an elastic collision with it. Thereafter, B makes completely inelastic collision with \(\mathrm{C}\). All motion occur on the same straight line. Find final speed of the object \(\mathrm{C}\) (A) \(3 \mathrm{~m} / \mathrm{s}\) (B) \(4 \mathrm{~m} / \mathrm{s}\) (C) \(5 \mathrm{~m} / \mathrm{s}\) (D) \(1 \mathrm{~m} / \mathrm{s}\)

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free