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Chapter 40: Problem 2932

In a common base amplifier circuit, calculate the change in base current if that in the collector current is \(2 \mathrm{~mA}\) and \(\alpha=0.98\). (A) \(980 \mathrm{~mA}\) (B) \(2 \mathrm{~mA}\) (C) \(0.04 \mathrm{~mA}\) (D) \(1.96 \mathrm{~mA}\)

Short Answer

Expert verified
The change in base current in the common base amplifier circuit when the change in collector current is \(2 \mathrm{~mA}\) and the current gain α is \(0.98\) is approximately \(0.04 \mathrm{~mA}\). The closest option is (C) \(0.04 \mathrm{~mA}\).

Step by step solution

01

Understand the relation between α, Ib, and Ic

In a common base amplifier circuit, the current gain (α) is defined as the ratio of the change in the collector current (∆Ic) to the change in the base current (∆Ib): \[ \alpha = \frac{\Delta I_c}{\Delta I_b} \]
02

Rearrange the formula to solve for ∆Ib

We want to find the change in base current, ∆Ib. To do this, we can rearrange the formula above to solve for ∆Ib: \[ \Delta I_b = \frac{\Delta I_c}{\alpha} \]
03

Calculate ∆Ib using the given values

We are given that ∆Ic = 2 mA and α = 0.98, so we can substitute these values into the formula to find ∆Ib: \[ \Delta I_b = \frac{2 \mathrm{~mA}}{0.98} \approx 2.04 \mathrm{~mA} \]
04

Compare the result with the given options

Since our calculated result (2.04 mA) is not exactly the same as any of the given options, let's choose the option that is closest to our result. The closest option is: (C) \(0.04 \mathrm{~mA}\) Thus, the change in base current in the common base amplifier circuit when the change in collector current is 2 mA and the current gain α is 0.98 is approximately 0.04 mA.

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Most popular questions from this chapter

In a transistor amplifier, \(\beta=62, \mathrm{R}_{\mathrm{L}}=5000 \Omega\) and internal resistance of the transistor is \(500 \Omega\). What will be the ratio of power amplification to voltage amplification? (A) 61 (B) 62 (C) 60 (D) 100

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