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Chapter 40: Problem 2935

What is the relation of the transistor current? (A) \(\mathrm{I}_{\mathrm{B}}=\mathrm{I}_{\mathrm{C}}+\mathrm{I}_{\mathrm{E}}\) (B) \(\mathrm{I}_{\mathrm{C}}=\mathrm{I}_{\mathrm{E}}+\mathrm{I}_{\mathrm{B}}\) (C) \(\mathrm{I}_{\mathrm{E}}=\mathrm{I}_{\mathrm{C}}+\mathrm{I}_{\mathrm{B}}\) (D) \(\mathrm{I}_{\mathrm{C}}=\mathrm{I}_{\mathrm{E}}+\mathrm{I}_{\mathrm{B}}\)

Short Answer

Expert verified
The short answer is: (C) \(\mathrm{I}_{\mathrm{E}}=\mathrm{I}_{\mathrm{C}}+\mathrm{I}_{\mathrm{B}}\).

Step by step solution

01

Recall Kirchhoff's Current Law (KCL)

Kirchhoff's Current Law states that the sum of currents entering a junction is equal to the sum of currents leaving the junction. We will apply KCL at the transistor junction, where the base current (\(\mathrm{I}_{\mathrm{B}}\)), collector current (\(\mathrm{I}_{\mathrm{C}}\)), and emitter current (\(\mathrm{I}_{\mathrm{E}}\)) meet.
02

Apply KCL to the transistor junction

Applying KCL to the transistor junction, we can write: \(\mathrm{I}_{\mathrm{E}}\) (incoming) = \(\mathrm{I}_{\mathrm{C}}\) (outgoing) + \(\mathrm{I}_{\mathrm{B}}\) (outgoing)
03

Compare the obtained relation with the given options

Rewriting the obtained relation, we have: \(\mathrm{I}_{\mathrm{E}}=\mathrm{I}_{\mathrm{C}}+\mathrm{I}_{\mathrm{B}}\) Comparing this relation with the given options, we can see that it matches with option (C). Therefore, the correct relation between the transistor currents is: (C) \(\mathrm{I}_{\mathrm{E}}=\mathrm{I}_{\mathrm{C}}+\mathrm{I}_{\mathrm{B}}\)

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Most popular questions from this chapter

In a common base amplifier circuit, calculate the change in base current if that in the collector current is \(2 \mathrm{~mA}\) and \(\alpha=0.98\). (A) \(980 \mathrm{~mA}\) (B) \(2 \mathrm{~mA}\) (C) \(0.04 \mathrm{~mA}\) (D) \(1.96 \mathrm{~mA}\)

Which of the following the correct relationship between two current gains \(\alpha\) and \(\beta\) in a transistor? (A) \(\beta=[(1+\alpha) / \alpha]\) (B) \(\beta=[\alpha /(1+\alpha)]\) (C) \(\alpha=[(1+\beta) / \beta]\) (D) \(\alpha=[\beta /(1+\beta)]\)

In a transistor, a change of \(8.0 \mathrm{~mA}\) in the emitter current produces a change of \(7.8 \mathrm{~mA}\) in the collector current. What change in the base current is necessary to produce the same change in the collector current? (A) \(300 \mu \mathrm{A}\) (B) \(400 \mu \mathrm{A}\) (C) \(200 \mu \mathrm{A}\) (D) \(100 \mu \mathrm{A}\)

In a common emitter amplifier, using output resistance of \(5000 \Omega\) and input resistance of \(2000 \Omega\), if the peak value of input signal voltage is \(10 \mathrm{mV}\) and \(\beta=50\) then what is the peak value of output voltage? (A) \(2.5 \times 10^{-4}\) Volt (B) \(5 \times 10^{-6}\) Volt (C) \(1.25\) Volt (D) 125 Volt

A transistor is connected in common emitter configuration. The collector supply is \(8 \mathrm{~V}\) and the voltage drop across a resistor of 800 in the collector circuit is \(0.5 \mathrm{~V}\). If the current gain factor \(\alpha\) is \(0.96\), then base current will be (A) \(27 \mu \mathrm{A}\) (B) \(26 \mu \mathrm{A}\) (C) \(25 \mu \mathrm{A}\) (D) \(24 \mu \mathrm{A}\)
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