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Chapter 5: Problem 632

Statement \(-1\) - Friction is necessary for a body to roll on surface. Statement \(-2\) - Friction provides the necessary tangential force and torque. \(\\{\mathrm{A}\\}\) Statement \(-1\) is correct (true), Statement \(-2\) is true and Statement- 2 is correct explanation for Statement \(-1\) \(\\{B\\}\) Statement \(-1\) is true, statement \(-2\) is true but statement- 2 is not the correct explanation four statement \(-1\). \(\\{\mathrm{C}\\}\) Statement \(-1\) is true, statement \(-2\) is false \\{D \\} Statement- 2 is false, statement \(-2\) is true

Short Answer

Expert verified
Option A: Statement 1 is true, Statement 2 is true, and Statement 2 is the correct explanation for Statement 1.

Step by step solution

01

Understanding Statement 1

Statement 1 claims that friction is necessary for a body to roll on a surface. This statement is accurate, as without friction, the body would not be able to grip the surface and initiate rolling motion. This implies that Statement 1 is true.
02

Understanding Statement 2

Statement 2 asserts that friction provides the necessary tangential force and torque. This statement is also accurate. When a body rolls on a surface, the force of friction acts tangentially. The torque generated by this frictional force allows the body to rotate and maintain its rolling motion. Thus, Statement 2 is true as well.
03

Evaluating the Relationship Between Statement 1 and Statement 2

Since Statement 2 explains the mechanism by which friction plays a significant role in a body's ability to roll on a surface, we can conclude that it is the correct explanation for Statement 1.
04

Selecting the Correct Option

Based on our reasoning and explanation, Option A is the correct one: Statement 1 is true, Statement 2 is true, and Statement 2 is the correct explanation for Statement 1.

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Most popular questions from this chapter

A car is moving at a speed of \(72 \mathrm{~km} / \mathrm{hr}\) the radius of its wheel is \(0.25 \mathrm{~m}\). If the wheels are stopped in 20 rotations after applying breaks then angular retardation produced by the breaks is \(\ldots .\) \(\\{\mathrm{A}\\}-25.5 \mathrm{rad} / \mathrm{s}^{2}\) \(\\{\mathrm{B}\\}-29.52 \mathrm{rad} / \mathrm{s}^{2}\) \(\\{\mathrm{C}\\}-33.52 \mathrm{rad} / \mathrm{s}^{2}\) \(\\{\mathrm{D}\\}-45.52 \mathrm{rad} / \mathrm{s}^{2}\)

What is the moment of inertia of a solid sphere of density \(\rho\) and radius \(\mathrm{R}\) about its diameter? \(\\{\mathrm{A}\\}(105 / 176) \mathrm{R}^{5} \rho\) \(\\{\mathrm{B}\\}(176 / 105) \mathrm{R}^{5} \rho\) \(\\{C\\}(105 / 176) R^{2} \rho\) \(\\{\mathrm{D}\\}(176 / 105) \mathrm{R}^{2} \rho\)

A Pulley of radius \(2 \mathrm{~m}\) is rotated about its axis by a force \(F=\left(20 t-5 t^{2}\right) N\) where \(t\) is in sec applied tangentially. If the moment of inertia of the Pulley about its axis of rotation is $10 \mathrm{KgM}^{2}$, the number of rotations made by the pulley before its direction of motion is reversed is : \(\\{\mathrm{A}\\}\) more than 3 but less then 6 \(\\{\mathrm{B}\\}\) more than 6 but less then 9 \(\\{\mathrm{C}\\}\) more than 9 \\{D \\} Less then 3

A solid cylinder of mass \(\mathrm{M}\) and radius \(\mathrm{R}\) rolls down an inclined plane of height \(\mathrm{h}\). The angular velocity of the cylinder when it reaches the bottom of the plane will be. \(\\{\mathrm{A}\\}(2 / \mathrm{R}) \sqrt{(\mathrm{gh})}\) \(\\{\mathrm{B}\\}(2 / \mathrm{R}) \sqrt{(\mathrm{gh} / 2)}\) \(\\{\mathrm{C}\\}(2 / \mathrm{R}) \sqrt{(\mathrm{gh} / 3)}\) \(\\{\mathrm{D}\\}(1 / 2 \mathrm{R}) \sqrt{(\mathrm{gh})}\)

One solid sphere \(\mathrm{A}\) and another hollow sphere \(\mathrm{B}\) are of the same mass and same outer radii. The moment of inertia about their diameters are respectively \(\mathrm{I}_{\mathrm{A}}\) and \(\mathrm{I}_{\mathrm{B}}\) such that... \(\\{\mathrm{A}\\} \mathrm{I}_{\mathrm{A}}=\mathrm{I}_{\mathrm{B}}\) \(\\{\mathrm{B}\\} \mathrm{I}_{\mathrm{A}}>\mathrm{I}_{\mathrm{B}}\) \(\\{\mathrm{C}\\} \mathrm{I}_{\mathrm{A}}<\mathrm{I}_{\mathrm{B}}\) $\\{\mathrm{D}\\}\left(\mathrm{I}_{\mathrm{A}} / \mathrm{I}_{\mathrm{B}}\right)=(\mathrm{d} \mathrm{A} / \mathrm{dB})$ (radio of their densities)
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