The largest and shortest distance of the earth from the sun are \(\mathrm{r}_{1}\) and \(\mathrm{r}_{2}\) its distance from the sun when it is at the perpendicular to the major axis of the orbit drawn from the sun (A) \(\left[\left(\mathrm{r}_{1}+\mathrm{r}_{2}\right) / 4\right]\) (B) $\left[\left(\mathrm{r}_{1} \mathrm{r}_{2}\right) /\left(\mathrm{r}_{1}+\mathrm{r}_{2}\right)\right]$ (C) \(\left[\left(2 r_{1} r_{2}\right) /\left(r_{1}+r_{2}\right)\right]\) (D) \(\left[\left(\mathrm{r}_{1}+\mathrm{r}_{2}\right) / 3\right]\)

Short Answer

Expert verified
The distance of the Earth from the Sun when it is at the perpendicular to the major axis of the orbit drawn from the Sun is \(\frac{r_1 + r_2}{2}\).

Step by step solution

01

Understand the properties of ellipses

An ellipse has two foci, and the sum of the distances from any point on the ellipse to the two foci is equal to a constant (the major axis length). For the Earth's orbit, the Sun is at one of the foci. Let F1 and F2 be the foci of the ellipse, and let P be any point on the ellipse. Then, the equation for the ellipse is given by: \[PF_1 + PF_2 = constant\] In our problem, F1 is at the Sun, and F2 is at the other focus.
02

Determine the relationship between the major and minor axes and the largest and shortest distances

The largest and shortest distances of the Earth from the Sun, \(r_1\) and \(r_2\), correspond to the endpoints of the major axis of the ellipse. The distance between the foci is \(2c\), where \(c\) is the distance from the center of the ellipse to one of its foci. Using the properties of ellipses, we can relate the major axis length, the minor axis length, and the distance between the foci: \[a^2 = b^2 + c^2\] where \(a\) is half of the major axis length (the semi-major axis) and \(b\) is half of the minor axis length (the semi-minor axis).
03

Find the expression for the distance when Earth is perpendicular to the major axis

When the Earth is at a position perpendicular to the major axis, the distances from the Earth to the foci, \(PF_1\) and \(PF_2\), are equal in length, since the Earth's position lies on the minor axis of the ellipse. Let the distance from the Earth to the Sun at this position be denoted by \(r\). Thus, we can write the equation for the ellipse as: \[2r = r_1 + r_2\] Solving for \(r\), we get: \[r = \frac{r_1 + r_2}{2}\]
04

Compare the obtained expression with the given options

Comparing our obtained expression for \(r\) with the given options, we can see that the correct option is: (A) \(\left[\left(\mathrm{r}_{1}+\mathrm{r}_{2}\right) / 4\right]\) So, the distance of the Earth from the Sun when it is at the perpendicular to the major axis of the orbit drawn from the Sun is \(\frac{r_1 + r_2}{2}\).

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