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Chapter 7: Problem 1003

In capillary pressure below the curved surface at water will be (A) Equal to atmospheric (B) Equal to upper side pressure (C) More than upper side pressure (D) Lesser than upper side pressure

Short Answer

Expert verified
The correct answer is (C) More than upper side pressure, as the capillary pressure below the curved surface must be more than the upper side pressure to maintain equilibrium and counteract the gravitational force, allowing the liquid to rise in the capillary.

Step by step solution

01

Option A: Equal to atmospheric

The capillary pressure below the curved surface is determined by the surface tension of liquid along with the curvature of the liquid-air interface. It can't be equal to atmospheric pressure directly as the curvature plays a significant role in capillary action.
02

Option B: Equal to upper side pressure

If the capillary pressure below the curved surface were equal to the upper side pressure, there would not be any change in pressure, and the liquid would not rise in the capillary. Hence, this option is also incorrect.
03

Option C: More than the upper side pressure

To maintain equilibrium and to counteract the gravitational force, the capillary pressure at the curved surface must be more than the upper side pressure (air pressure). This additional pressure generates a net upward force allowing the liquid to rise in the capillary. Therefore, this option is correct.
04

Option D: Lesser than the upper side pressure

If the capillary pressure below the curved surface was lesser than the upper side pressure, the liquid would not rise in the capillary. Instead, it would force the liquid to sink down. Thus, this option is not accurate. Hence, based on the analysis and understanding of the capillary pressure below the curved surface at water, the correct answer is: (C) More than upper side pressure

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Most popular questions from this chapter

Shearing stress causes change in (A) length (B) breadth (C) shape (D) volume

Water raises in a vertical capillary tube upto a height of \(2.0\) \(\mathrm{cm}\). If tube is inclined at an angle of \(60^{\circ}\) with the vertical then the what length the water will rise in the tube. (A) \(2.0 \mathrm{~cm}\) (B) \(4.0 \mathrm{~cm}\) (C) \((4 / \sqrt{3}) \mathrm{cm}\) (D) \(2 \sqrt{2} \mathrm{~cm}\)

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