If temperature of an object is \(140^{\circ} \mathrm{F}\) then its temperature in centigrade is (A) \(105^{\circ} \mathrm{C}\) (B) \(32^{\circ} \mathrm{C}\) (C) \(140^{\circ} \mathrm{C}\) (D) \(60^{\circ} \mathrm{C}\)

Short Answer

Expert verified
The correct answer is (D) \(60^{\circ} \mathrm{C}\), which is obtained by using the Fahrenheit to Celsius conversion formula \(C = (F - 32) × \frac{5}{9}\) and plugging in the given temperature of \(140^{\circ} \mathrm{F}\).

Step by step solution

01

Write down the given temperature in Fahrenheit

We are given the temperature of an object as \(140^{\circ} \mathrm{F}\).
02

Use the conversion formula to convert the temperature into Celsius

The formula for converting Fahrenheit to Celsius is: \[C = (F - 32) × \frac{5}{9}\] Now, plug in the given Fahrenheit temperature (F = 140) into the formula: \[C = (140 - 32) × \frac{5}{9}\]
03

Calculate the Celsius temperature

Perform the calculations inside the parentheses first, and then multiply by the fraction: \[C = (108) × \frac{5}{9}\] Divide 108 by 9: \[C = 12 × 5\] Now, multiply 12 by 5: \[C = 60\] Thus, the temperature in Celsius is \(60^{\circ} \mathrm{C}\). The correct answer is (D) \(60^{\circ} \mathrm{C}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A square frame of side \(\mathrm{L}\) is dipped in a liquid on taking out a membrance is formed if the surface tension of the liquid is \(\mathrm{T}\), the force acting on the frame will be. (A) \(2 \mathrm{TL}\) (B) \(4 \mathrm{TL}\) (C) \(8 \mathrm{TL}\) (D) \(10 \mathrm{TL}\)

A thin liquid film formed between a u-shaped wire and a light slider supports a weight of \(1.5 \times 10^{-2} \mathrm{~N}\) (see figure). The length of the slider is \(30 \mathrm{~cm}\) and its weight negligible. The surface tension of the liquid film is. (A) \(0.0125 \mathrm{Nm}^{-1}\) (B) \(0.1 \mathrm{Nm}^{-1}\) (C) \(0.05 \mathrm{Nm}^{-1}\) (D) \(0.025 \mathrm{Nm}^{-1}\)

A material has poisson's ratio \(0.50\). If uniform rod of it suffers longitudinal strain of \(2 \times 10^{-3}\). Then what is percentage change in volume ? (A) \(0.6\) (B) \(0.4\) (C) \(0.2\) (D) 0

Two solid spheres of same metal but of mass \(\mathrm{M}\) and \(8 \mathrm{M}\) full simultaneously on a viscous liquid and their terminal velocity are \(\mathrm{V}\) and ' \(\mathrm{nV}^{\prime}\) then value of 'n' is (A) 16 (B) 8 (C) 4 (D) 2

A tank is filled with water up to a height \(\mathrm{H}\). Water is allowed to come out of a hole P in one of the walls at a depth \(\mathrm{D}\) below the surface of water express the horizontal distance \(\mathrm{x}\) in terms of \(\mathrm{H}\) and \(\mathrm{D}\). (B) $\left.\mathrm{x}={ }^{\alpha} \sqrt{[}\\{\mathrm{D}(\mathrm{H}-\mathrm{D})\\} / 2\right]$ (D) \(\mathrm{x}=4[\mathrm{D}(\mathrm{H}-\mathrm{D})]\)

See all solutions

Recommended explanations on English Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free