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Chapter 7: Problem 1067

Amount of heat required to raise the temperature of a body through $1 \mathrm{k}$ is called it is (A) Water equivalent (B) Thermal capacity (C) Entropy (D) Specific heat

Short Answer

Expert verified
The correct answer is (D) Specific Heat, as it is the amount of heat energy required to raise the temperature of a unit mass of a substance by 1 Kelvin (or 1 degree Celsius).

Step by step solution

01

A) Water Equivalent

The water equivalent of a body is the mass of water that would absorb or lose the same amount of heat as the body for the same temperature change. The concept of water equivalent is used to compare the thermal behavior of a substance to that of water.
02

B) Thermal Capacity

Thermal capacity, also known as heat capacity, is the amount of heat needed to change the temperature of an object by 1 degree Celsius or 1 Kelvin. It depends on both the mass and the material of the object. The formula is given by: \[ C = mc \] where `C` is the heat capacity, `m` is the mass, and `c` is the specific heat.
03

C) Entropy

Entropy is a physical quantity that measures the degree of randomness or disorder within a system. It is related to the concept of energy distribution across particles in the system, and it helps us understand the spontaneous behavior of a thermodynamic system or process.
04

D) Specific Heat

Specific heat, also known as specific heat capacity, is the amount of heat energy required to raise the temperature of a unit mass of a substance by 1 Kelvin (or 1 degree Celsius). It is a property of the material that makes up an object and varies from one substance to another. The formula for specific heat is given by: \[ q = mcΔT \] where `q` is the heat transferred, `m` is the mass, `c` is the specific heat, and `ΔT` is the change in temperature. Now, as per the given exercise, we need to find the amount of heat required to raise the temperature of a body through 1K. Looking at the above descriptions and formulas, we can determine that the correct answer is: (D) Specific heat

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