The temperature of a wire of length 1 meter and area of cross-sectional section \(1 \mathrm{~cm}^{2}\) is increased from \(0^{\circ}\) to $100^{\circ} \mathrm{C}$. If the rod is not allowed to increase in length. What will be the force required ? $\left[\alpha=10^{-5} /{ }^{\circ} \mathrm{C}, \mathrm{Y}=10^{11}\left(\mathrm{~N} / \mathrm{m}^{2}\right)\right]$ (A) \(10^{3} \mathrm{~N}\) (B) \(10^{4} \mathrm{~N}\) (C) \(10^{5} \mathrm{~N}\) (D) \(10^{9} \mathrm{~N}\)

Short Answer

Expert verified
The force required to prevent the wire from expanding is \(10^{4} N\). So, the correct answer is (B).

Step by step solution

01

1. Convert area to the proper unit

Since the given area is in cm², we need to convert it to m²: Area = 1 cm² = 0.0001 m²
02

2. Calculate the change in length of the wire

Using the linear expansion formula, we can calculate the change in length: ΔL = α * L * ΔT Where: α = 10⁻⁵ /°C (coefficient of linear expansion) L = 1 m (initial length of the wire) ΔT = 100 °C (change in temperature) ΔL = (10⁻⁵ /°C)(1 m)(100 °C) = 0.001 m
03

3. Calculate the extension (strain) of the wire

Strain is the ratio of the change in length to the original length: Strain = ΔL / L Strain = 0.001 m / 1 m = 0.001
04

4. Use Young's modulus to find the stress

Now we can use the formula for Young's modulus: Y = stress / strain Where Y is the Young's modulus and is given as 10¹¹ N/m². We can rearrange the formula to find the stress: Stress = Y * strain Stress = (10¹¹ N/m²)(0.001) = 10⁸ N/m²
05

5. Find the force required to prevent the wire from expanding

Now we have the stress, we can find the force using the formula: Force = Stress * Area Force = (10⁸ N/m²)(0.0001 m²) = 10⁴ N The force required to prevent the wire from expanding is 10⁴ N. So, the correct answer is (B).

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