In steel the young's modulus and the strain at the breaking point are $2 \times 10^{11}\left(\mathrm{~N} / \mathrm{m}^{2}\right)\( and \)0.15$ respectively the stress at the breaking point for steel is therefore........... (A) \(1.33 \times 10^{11}\left(\mathrm{~N} / \mathrm{m}^{2}\right)\) (B) \(1.33 \times 10^{12}\left(\mathrm{~N} / \mathrm{m}^{2}\right)\) (C) \(7.5 \times 10^{-13}\left(\mathrm{~N} / \mathrm{m}^{2}\right)\) (D) \(3 \times 10^{10}\left(\mathrm{~N} / \mathrm{m}^{2}\right)\)

Short Answer

Expert verified
The stress at the breaking point for steel is \(3 \times 10^{10}\mathrm{~N/m^2}\).

Step by step solution

01

Identify the given values and formula

We are given: - Young's Modulus (E) = \(2 \times 10^{11} \mathrm{~N/m^2}\) - Strain at the breaking point (ε) = 0.15 We will use the formula: σ = E ε
02

Calculate the stress at the breaking point

Plug the given values into the formula: σ = \((2 \times 10^{11})(0.15)\)
03

Solve for the stress at the breaking point

Multiplying the given values, we get: σ = \(3 \times 10^{10}\mathrm{~N/m^2}\)
04

Match the calculated stress with the given options

We look for the option that matches our calculated stress: (A) \(1.33 \times 10^{11}\mathrm{~N/m^2}\) (Incorrect) (B) \(1.33 \times 10^{12}\mathrm{~N/m^2}\) (Incorrect) (C) \(7.5 \times 10^{-13}\mathrm{~N/m^2}\) (Incorrect) **(D) \(3 \times 10^{10}\mathrm{~N/m^2}\) (Correct)** Thus, the stress at the breaking point for steel is \(3 \times 10^{10}\mathrm{~N/m^2}\), and the correct answer is (D).

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