Chapter 7: Problem 978
When there is no external force, the shape of liquid drop is determined by (A) Surface tension of liquid (B) Density of Liquid (C) Viscosity of liquid (D) Temperature of air only
Chapter 7: Problem 978
When there is no external force, the shape of liquid drop is determined by (A) Surface tension of liquid (B) Density of Liquid (C) Viscosity of liquid (D) Temperature of air only
All the tools & learning materials you need for study success - in one app.
Get started for freeTwo solid spheres of same metal but of mass \(\mathrm{M}\) and \(8 \mathrm{M}\) full simultaneously on a viscous liquid and their terminal velocity are \(\mathrm{V}\) and ' \(\mathrm{nV}^{\prime}\) then value of 'n' is (A) 16 (B) 8 (C) 4 (D) 2
The fraction of floating object of volume \(\mathrm{V}_{0}\) and density \(\mathrm{d}_{0}\) above the surface of a Liquid as density \(\mathrm{d}\) will be (A) \(\left(\mathrm{d}_{0} / \mathrm{d}\right)\) (B) $\left[\left\\{\mathrm{dd}_{0}\right\\} /\left\\{\mathrm{d}+\mathrm{d}_{0}\right\\}\right]$ (C) \(\left[\left\\{d-d_{0}\right\\} / d\right]\) (D) $\left[\left\\{\mathrm{dd}_{0}\right\\} /\left\\{\mathrm{d}-\mathrm{d}_{0}\right\\}\right]$
8000 identical water drops are combined to form a bigdrop. Then the ratio of the final surface energy to the initial surface energy of all the drops together is (A) \(1: 10\) (B) \(1: 15\) (C) \(1: 20\) (D) \(1: 25\)
For a constant hydraulic stress on an object, the fractional change in the object volume \([\Delta \mathrm{V} / \mathrm{V}]\) and its bulk modulus (B) are related as............ (A) \((\Delta \mathrm{V} / \mathrm{V}) \alpha \beta\) (B) \((\Delta \mathrm{V} / \mathrm{V}) \alpha \beta^{-1}\) (C) \((\Delta \mathrm{V} / \mathrm{V}) \alpha \beta^{2}\) (D) \((\Delta \mathrm{V} / \mathrm{V}) \alpha \beta^{-2}\)
Which is the dimensional formula for modulus of rigidity? (A) \(\mathrm{M}_{1} \mathrm{~L}^{1} \mathrm{~T}^{-2}\) (B) \(\mathrm{M}^{1} \mathrm{~L}^{-1} \mathrm{~T}^{-2}\) (C) \(\mathrm{M}^{1} \mathrm{~L}^{-2} \mathrm{~T}^{-1}\) (D) \(\mathrm{M}^{1} \mathrm{~L}^{-2} \mathrm{~T}^{-2}\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.