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Chapter 8: Problem 1089

The temperature on Celsius scale is \(25^{\circ} \mathrm{C}\). What is the corresponding temperature on the Fahrenheit Scale? (A) \(40^{\circ} \mathrm{F}\) (B) \(45^{\circ} \mathrm{F}\) (C) \(50^{\circ} \mathrm{F}\) (D) \(77^{\circ} \mathrm{F}\)

Short Answer

Expert verified
The corresponding temperature on the Fahrenheit scale is \(77^{\circ} \mathrm{F}\). (D)

Step by step solution

01

Write down the formula to convert Celsius to Fahrenheit

We begin by writing down the formula needed for this conversion: \(F = \frac{9}{5}C + 32\)
02

Substitute the given value for C

Given that the temperature in Celsius is 25ºC, we replace C with 25 in the formula: \(F = \frac{9}{5}(25) + 32\)
03

Calculate the temperature in Fahrenheit

Now, we perform the calculations to find the temperature in Fahrenheit: \(F = \frac{9}{5}(25) + 32 = \frac{9(25)}{5} + 32 = 45 + 32\) \(F = 77\)
04

Find the corresponding answer

With the knowledge that the temperature in Fahrenheit is 77ºF, we look at the answer choices and find that: (D) \(77^{\circ} \mathrm{F}\) So, the correct answer for the problem is choice (D).

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Most popular questions from this chapter

\(\mu\) moles of gas expands from volume \(\mathrm{V}_{1}\) to \(\mathrm{V}_{2}\) at constant temperature \(\mathrm{T}\). The work done by the gas is (A) \(\mu \mathrm{RT}\left\\{\mathrm{V}_{2} / \mathrm{V}_{1}\right\\}\) (B) \(\mu \operatorname{RTln}\left\\{\mathrm{V}_{2} / \mathrm{V}_{1}\right\\}\) (C) $\mu \mathrm{RT}\left\\{\left(\mathrm{V}_{\mathrm{v}} / \mathrm{V}_{1}\right)-1\right\\}$ (D) $\mu \operatorname{RTln}\left\\{\left(\mathrm{V}_{2} / \mathrm{V}_{1}\right)\right.$

The efficiency of Carnot's engine operating between reservoirs, maintained at temperature \(27^{\circ} \mathrm{C}\) and \(-123^{\circ} \mathrm{C}\) is (A) \(0.5\) (B) \(0.4\) (C) \(0.6\) (D) \(0.25\)

A diatomic gas initially at \(18^{\circ} \mathrm{C}\) is Compressed adiabatically to one eighth of its original volume. The temperature after Compression will be (A) \(10^{\circ} \mathrm{C}\) (B) \(668 \mathrm{~K}\) (C) \(887^{\circ} \mathrm{C}\) (D) \(144^{\circ} \mathrm{C}\)

A gas expands \(0.25 \mathrm{~m}^{3}\) at Constant Pressure \(10^{3}\left(\mathrm{~N} / \mathrm{m}^{2}\right)\) the work done is (A) \(250 \mathrm{~J}\) (B) \(2.5\) erg (C) \(250 \mathrm{~W}\) (D) \(250 \mathrm{~N}\)

If du represents the increase in internal energy of a thermodynamic system and dw the work done by the system, which of the following statement is true? (A) \(\mathrm{du}=\mathrm{dw}\) in isothermal process (C) \(\mathrm{du}=-\mathrm{dw}\) in an aidabatic process (B) \(\mathrm{du}=\mathrm{dw}\) in aidabatic process (D) \(\mathrm{du}=-\mathrm{dw}\) in an isothermal process
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