One mole of a monoatomic gas is heat at a constant pressure of 1 atmosphere from \(0 \mathrm{k}\) to \(100 \mathrm{k}\). If the gas constant $\mathrm{R}=8.32 \mathrm{~J} / \mathrm{mol} \mathrm{k}$ the change in internal energy of the gas is approximate ? (A) \(23 \mathrm{~J}\) (B) \(1.25 \times 10^{3} \mathrm{~J}\) (C) \(8.67 \times 10^{3} \mathrm{~J}\) (D) \(46 \mathrm{~J}\)

Short Answer

Expert verified
The change in internal energy of the monoatomic gas is approximately \(1.25 \times 10^{3} \mathrm{~J}\).

Step by step solution

01

Find the value of Cv for monoatomic gas

Monoatomic gases have a constant volume heat capacity (Cv) equal to (3/2)R, where R is the gas constant (Given: R = 8.32 J/mol K). So, let's find the value of Cv: Cv = (3/2) * R Cv = (3/2) * 8.32 J/mol K Cv ≈ 12.48 J/mol K
02

Calculate the change of internal energy using the formula for ΔU (Cv)

Now, from the given initial and final temperatures, we can determine the change in temperature (ΔT). Then, we will use the formula for the change in internal energy ΔU with the values of n, Cv, and ΔT that we have. ΔT = T(final) - T(initial) ΔT = 100 K - 0 K ΔT = 100 K ΔU = nCvΔT ΔU = (1 mol) (12.48 J/mol K) (100 K) ΔU ≈ 1248 J Since the change in internal energy is approximately equal to 1248 J, the correct answer is: (B) 1.25 x 10^3 J

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