Two blocks of the same density are completely submerged in water. One block has a mass equal to \(m\) and volume equal to \(V\). The other has a mass equal to \(2 m\). What is the ratio of the first block's apparent weight to the second block's apparent weight? 1\. \(1: 1\) 2\. \(1: 2\) 3\. \(2: 1\) \(\begin{array}{lll}\text { 4. } & 4: 1\end{array}\)

Short Answer

Expert verified
The ratio of the first block's apparent weight to the second block's apparent weight is 1:2.

Step by step solution

01

Find the Density of Blocks

Since both blocks have the same density, let's denote the density as 'ρ'. Using mass and volume, we can write: \[\rho = \frac{m}{V}\]
02

Volume of the Second Block

Since the two blocks have the same density and the second block has double the mass of the first block, we can find the volume of the second block: \[\rho = \frac{2m}{V_2}\] Now from Step 1, substitute the value of density: \[\frac{m}{V} = \frac{2m}{V_2}\] Solving for the volume of the second block: \[V_2 = 2V\]
03

Calculate Buoyant Forces

The buoyant force experienced by each block can be found using Archimedes' principle, which states that the upward buoyant force experienced by a submerged object is equal to the weight of the fluid it displaces. This can be written as: \[F_b = \rho_{water} \cdot V \cdot g\] For the first block, the buoyant force is: \[F_{b1} = \rho_{water} \cdot V \cdot g\] For the second block, using the volume from Step 2: \[F_{b2} = \rho_{water} \cdot 2V \cdot g\]
04

Calculate Apparent Weights

Apparent weight is the difference between an object's actual weight and the buoyant force acting on it. Let's find the apparent weights of both blocks. For the first block: \[W_{a1} = m \cdot g - F_{b1}\] For the second block: \[W_{a2} = 2m \cdot g - F_{b2}\]
05

Calculate the Ratio Apparent Weights

Now, we need to find the ratio of apparent weights of the first block to the second block: \[\frac{W_{a1}}{W_{a2}}\] Using the expressions for apparent weights from Step 4: \[\frac{m \cdot g - F_{b1}}{2m \cdot g - F_{b2}}\] Using the buoyant forces from Step 3: \[\frac{m \cdot g - \rho_{water} \cdot V \cdot g}{2m \cdot g - \rho_{water} \cdot 2V \cdot g}\] Factor out common terms: \[\frac{m( g - \rho_{water} \cdot V \cdot g)}{2m( g - \rho_{water} \cdot V \cdot g)}\] Simplifying the expression: \[\frac{m}{2m} = \frac{1}{2}\] The ratio of the first block's apparent weight to the second block's apparent weight is 1:2, which corresponds to answer choice 2.

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