When an electron falls from \(\mathrm{n}=3\) to \(\mathrm{n}=2\) in a hydrogen atom, what is the value of the energy released, given that \(A\) is the energy needed to remove an electron from the ground state of a hydrogen atom to an infinite distance from the atom? 1\. \(0.14 \mathrm{~A}\) 2\. \(0.17 \mathrm{~A}\) 3\. \(1.00 \mathrm{~A}\) 4\. \(5.00 \mathrm{~A}\)

Short Answer

Expert verified
The energy released is \(0.14 \mathrm{~A}\).

Step by step solution

01

Finding The Energy Difference Formula

The energy difference between two energy levels, n1 and n2, in a hydrogen atom can be found using the Rydberg formula: \[ E = -A \left(\frac{1}{n1^2} - \frac{1}{n2^2} \right) \] In our case, n1 = 2 and n2 = 3, and A is the energy needed to remove an electron from the ground state to an infinite distance from the atom.
02

Substituting The Values

Now, we substitute the values of n1 and n2 into the equation: \[ E = -A \left(\frac{1}{(2)^2} - \frac{1}{(3)^2} \right) \]
03

Simplifying The Equation

Simplify the equation to obtain the energy difference: \[ E = A \left( \frac{1}{4} - \frac{1}{9} \right) \]
04

Finding The Common Denominator

Find a common denominator to further simplify the equation: \[ E = A \left( \frac{9 - 4}{(4)(9)} \right) \]
05

Simplifying The Fractions

Simplify the fractions: \[ E = A \left(\frac{5}{36}\right) \] Now, express the energy released as a fraction of A: \[ \frac{E}{A} = \frac{5}{36} \]
06

Converting To Decimal and Choose the Correct Option

Convert the fraction to a decimal: \[ \frac{5}{36} \approx 0.14 \] Therefore, the energy released is 0.14A. The correct answer is option 1. \(0.14 \mathrm{~A}\).

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