Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 1: Problem 4

A myopic person's eye has a relaxed focal length of \(1.9 \mathrm{~cm}\). What is the maximum distance from the eye at which she can see an object clearly, and what is the magnification of the lens for an object at this point? A. \(0=1 \mathrm{~cm}, m=-\frac{1}{2}\) B. \(0=38 \mathrm{~cm}, m=-\frac{1}{38}\) C. \(0=38 \mathrm{~cm}, n=-\frac{1}{19}\) D. \(0=50 \mathrm{~cm}, \mathrm{mt}=-\frac{1}{50}\)

Short Answer

Expert verified
The maximum object distance is \(1.9 \mathrm{~cm}\), and the magnification is \(-1\). None of the given options match this answer.

Step by step solution

01

Determine the maximum object distance

To find the maximum distance at which the person can see the object clearly, she will need to see it at the farthest point she can focus the light from the object onto her retina. This occurs when the image distance (i) is at its minimum. For a myopic person, this minimum image distance corresponds to the relaxed state of her eye. The relaxed focal length is given by 1.9 cm in this case. Therefore, i = 1.9 cm. Now, let's use the lens formula to find the maximum object distance (o): \(\frac{1}{f} = \frac{1}{o} + \frac{1}{i}\) Substitute f = 1.9 cm and i = 1.9 cm into the formula: \(\frac{1}{1.9} = \frac{1}{o} + \frac{1}{1.9}\)
02

Solve for the maximum object distance (o)

Simplify the equation and solve for o: \(\frac{1}{o} = \frac{1}{1.9} - \frac{1}{1.9}\) \(\frac{1}{o} = \frac{1}{1.9}\) Flip both sides: o = 1.9 cm So, the maximum object distance at which she can see an object clearly is 1.9 cm.
03

Calculate the lens magnification (m)

Now we will calculate the magnification using the formula: m = -\(\frac{i}{o}\) Substitute the values for i = 1.9 cm and o = 1.9 cm: m = -\(\frac{1.9}{1.9}\) m = -1 The lens magnification at this point is -1. The maximum object distance is 1.9 cm, and the magnification is -1. Comparing the answer to the available options, we can see that none of them match the correct solution. This means, there might be a typographical error in the given options, or the context of the question might have been incorrectly understood.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of the following describes the effect on boiling point when a nonvolatile solute is added to a liquid? 1\. \(\Delta T_b=K_b M\) 2\. \(\Delta T_b=K_b / M\) 3\. \(\Delta T_b=K_b m\) 4\. \(\quad \Delta T_b=K_b / m\)

Why does an incandescent light have a longer life when an inert gas is used rather than a vacuum? 1\. The filament vaporizes more slowly. 2\. Heat is removed from the filament. 3\. The bulb is less likely to implode when subjected to vibration. 4\. The gas directly absorbs energy from the electrons in the filament.

Gas \(\mathrm{A}\) is at \(30{ }^{\circ} \mathrm{C}\) and gas \(\mathrm{B}\) is at \(20^{\circ} \mathrm{C}\). Both gases are at 1 atmosphere. What is the ratio of the volume of 1 mole of gas A to 1 mole of gas B? 1\. \(1: 1\) 2\. \(2: 3\) 3\. \(3: 2\) 4\. \(303: 293\)

Which kind of lamp, incandescent or fluorescent, is more efficient? 1\. Incandescent lamps, because they release all of the radiation they originally produce 2\. Fluorescent lamps, because they produce only radiation in the visible range 3\. Incandescent lamps, because no energy is lost in the conversion of energy from one wavelength to another 4\. Fluorescent lamps, because they multiply the intensity of radiation as it is converted from ultraviolet to visible light

What would a manufacturer of fluorescent lamps have to do in order to change his "warm white" lamps to "cool white" lamps? 1\. Change the amount of mercury vapor in the lamp to produce less ultraviolet light. 2\. Change the thickness of the glass tube to get a greater index of refraction. 3\. Change the composition of the electrodes to produce a weaker electric arc. 4\. Change the composition of the phosphor to emit more light at the blue- violet end of the spectrum.
See all solutions

Recommended explanations on English Textbooks

Phonetics

Read Explanation

Listening and Speaking

Read Explanation

Rhetoric

Read Explanation

Cues and Conventions

Read Explanation

Sociolinguistics

Read Explanation

International English

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free