If \(z=-3\), what is \(\frac{z^3+2 z+3}{z^2+1}\) ? A. 3 B. -1.8 C. -3.6 D. -3

Short Answer

Expert verified
D. -3

Step by step solution

01

Substitute z with the given value #-3

Replace z with -3 in the given expression \(\frac{z^3+2z+3}{z^2+1}\). \[ \frac{(-3)^3+2(-3)+3}{(-3)^2+1} \]
02

Solve the numerator and denominator separately

Calculate the value of the expression on the top and the bottom separately. \[ \frac{(-3)^3+2(-3)+3}{(-3)^2+1} = \frac{(-27)+(-6)+3}{9+1} \]
03

Simplify the expression

Combine the values in the numerator and the denominator to obtain the final simplified result. \[ \frac{(-27)+(-6)+3}{9+1} = \frac{-30}{10} \]
04

Divide the numerator by the denominator

Now perform the division of the numerator with the denominator to get the final result. \[ \frac{-30}{10} = -3 \] The value of the expression \(\frac{z^3+2z+3}{z^2+1}\) is -3 when \(z=-3\). Thus, the correct answer is: D. -3

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