Chapter 13: Problem 2
Overhead sunlight arrives on the surface of the earth at an intensity of about \(1,000 \mathrm{~W} / \mathrm{m}^{2}\). How many photons per second strike a solar panel whose area is \(1.6\) square meters, if the typical wavelength is \(\lambda=0.5 \mu \mathrm{m} ?\)
Short Answer
Expert verified
Answer: Approximately 4.02 × 10^21 photons per second.
Step by step solution
01
Calculate energy from intensity and area
To find the energy, multiply the intensity of sunlight (1,000 W/m^2) by the area of the solar panel (1.6 m^2):
Energy (E) = Intensity (I) × Area (A)
E = 1,000 W/m^2 × 1.6 m^2
E = 1,600 W
02
Calculate frequency from wavelength
Dividing the speed of light (c ≈ 3 × 10^8 m/s) by the wavelength (λ = 0.5 × 10^-6 m), we get the frequency (v):
Frequency (v) = Speed of light (c) / Wavelength (λ)
v = (3 × 10^8 m/s) / (0.5 × 10^-6 m)
v ≈ 6 × 10^14 Hz
03
Calculate energy of a photon
Next, we use Planck's constant (h ≈ 6.63 × 10^-34 J·s) to calculate the energy of a photon:
Energy of a photon (E_photon) = Planck's constant (h) × Frequency (v)
E_photon = (6.63 × 10^-34 J·s) × (6 × 10^14 Hz)
E_photon ≈ 3.98 × 10^-19 J
04
Calculate the number of photons per second
Finally, divide the energy (E = 1,600 W) by the energy of a photon (E_photon ≈ 3.98 × 10^-19 J) to find the number of photons per second (N):
Number of photons per second (N) = Energy (E) / Energy of a photon (E_photon)
N = (1,600 W) / (3.98 × 10^-19 J)
N ≈ 4.02 × 10^21 photons/s
The solar panel receives approximately 4.02 × 10^21 photons per second.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Photon Energy Calculation
The calculation of a photon's energy is essential in understanding how solar panels convert light into electricity. Photons are particles of light, and each one carries a certain amount of energy determined by its wavelength or frequency. To calculate this energy, we use the fundamental relationship derived from quantum physics, where the energy (\( E \)) of a photon is the product of Planck's constant (\( h \text{, which is approximately }6.63 \times 10^{-34} \text{ J·s}\text{, and} \text{the frequency} \text{(} \text{v} \text{)} \text{of the light} \).
The formula to find a photon's energy is:
\[ E_{\text{photon}} = h \times u \]
Given the frequency, which we can calculate by dividing the speed of light (\( c \text{, roughly }3 \times 10^8 \text{ m/s}\text{)} \text{by the wavelength} \text{(} \lambda \text{)} \), we find the energy of an individual photon. This understanding enables us to quantify the amount of energy a solar panel can harness from sunlight, leading to applications in solar energy technologies and the calculation of the efficiency of photovoltaic cells.
For the given exercise, knowing the intensity of sunlight and the area of the solar panel allows us to calculate the number of photons striking the panel per second, which in turn gives us insight into the potential electrical energy that can be generated.
The formula to find a photon's energy is:
\[ E_{\text{photon}} = h \times u \]
Given the frequency, which we can calculate by dividing the speed of light (\( c \text{, roughly }3 \times 10^8 \text{ m/s}\text{)} \text{by the wavelength} \text{(} \lambda \text{)} \), we find the energy of an individual photon. This understanding enables us to quantify the amount of energy a solar panel can harness from sunlight, leading to applications in solar energy technologies and the calculation of the efficiency of photovoltaic cells.
For the given exercise, knowing the intensity of sunlight and the area of the solar panel allows us to calculate the number of photons striking the panel per second, which in turn gives us insight into the potential electrical energy that can be generated.
Planck's Constant Application
Planck's constant (\( h \text{)} \) is a fundamental constant in quantum mechanics that plays a pivotal role in the energy of photons. Its application extends far beyond a simple number; it represents the quantization of energy and is essential in the field of quantum physics. Within the context of solar energy, Planck's constant is used to calculate the energy of photons, which can be absorbed by solar panels to generate electricity.
When applied together with the frequency of the light, Planck's constant gives us precise knowledge about the energy a photon carries. This understanding is crucial since solar panels are designed to capture this energy and convert it into a usable electrical form. By computing the energy of each photon and knowing the total number of photons that hit a panel, we can estimate the maximum energy output that a solar panel might produce under ideal conditions.
The application of Planck's constant in our textbook exercise allowed us to identify the energy each photon possesses, bridging the gap between the abstract quantum world and practical solar energy harvesting.
When applied together with the frequency of the light, Planck's constant gives us precise knowledge about the energy a photon carries. This understanding is crucial since solar panels are designed to capture this energy and convert it into a usable electrical form. By computing the energy of each photon and knowing the total number of photons that hit a panel, we can estimate the maximum energy output that a solar panel might produce under ideal conditions.
The application of Planck's constant in our textbook exercise allowed us to identify the energy each photon possesses, bridging the gap between the abstract quantum world and practical solar energy harvesting.
Solar Radiation Intensity
Solar radiation intensity refers to the power per unit area received from the Sun in the form of electromagnetic radiation. Measured in watts per square meter (\( W/m^2 \text{)} \), it is a crucial factor in calculating the potential energy available from sunlight for solar panels. The intensity of solar radiation can vary based on factors such as the time of day, atmospheric conditions, and geographical location.
In the context of the textbook exercise, an intensity of roughly 1,000 W/m^2 is considered, which is close to the solar constant, the average amount of solar radiation that reaches the Earth's upper atmosphere on a surface perpendicular to the Sun's rays. By understanding solar radiation intensity, we can gauge the maximum energy that a given area of a solar panel can receive and thus predict the potential electricity generation.
Additionally, solar radiation intensity informs us about the concentration of photons arriving at the solar panel, and when combined with the knowledge of photon energy, it contributes to understanding the overall efficiency of solar panels. This concept is fundamental for anyone interested in solar energy adoption and maximizing the utilization of this renewable energy source.
In the context of the textbook exercise, an intensity of roughly 1,000 W/m^2 is considered, which is close to the solar constant, the average amount of solar radiation that reaches the Earth's upper atmosphere on a surface perpendicular to the Sun's rays. By understanding solar radiation intensity, we can gauge the maximum energy that a given area of a solar panel can receive and thus predict the potential electricity generation.
Additionally, solar radiation intensity informs us about the concentration of photons arriving at the solar panel, and when combined with the knowledge of photon energy, it contributes to understanding the overall efficiency of solar panels. This concept is fundamental for anyone interested in solar energy adoption and maximizing the utilization of this renewable energy source.