The outcome of Problem 5 indicates that a hot light bulb filament emits thousands of times more power per unit area than human skin. Yet both a human and a light bulb may emit a similar amount of light \(^{105}\) - both around \(100 \mathrm{~W}\). Explain how both things can be true?

Short Answer

Expert verified
Both the hot light bulb filament and human skin can emit a similar amount of light due to different factors that contribute to the total emitted energy. The filament has a much higher power per unit area, but its surface area is smaller compared to the human body. On the other hand, human skin has a lower power per unit area but a larger surface area. The combined effect of the temperature, emissive properties, and surface area of these two objects result in a similar amount of emitted energy, allowing them to emit a comparable amount of light.

Step by step solution

01

Understand Emission of Energy

The emission of energy depends on both the temperature and the emissive properties of an object. In this case, we are looking at a hot light bulb filament and human skin. The light bulb filament is at a much higher temperature, which is why it emits more power per unit area. On the other hand, human skin is at a relatively lower temperature, but it covers a larger surface area.
02

Consider the Surface Area

The total amount of emitted energy depends not only on the power per unit area but also on the overall surface area. A human body has a much larger surface area compared to that of a light bulb filament.
03

Calculate the Total Emitted Energy

To calculate the total emitted energy, we need to multiply the power per unit area by the surface area. Since the power per unit area of the filament is much higher, but the surface area is smaller, it's possible for the product of these two factors to be similar to that of human skin. Conversely, the power per unit area of human skin is lower but, due to having a larger surface area, it can result in a similar amount of emitted light.
04

Conclusion

Both the hot light bulb filament and human skin can emit a similar amount of light, even though a filament has a higher power per unit area. This is because the filament has a smaller surface area compared to the human body. The larger surface area of the human body compensates for the lower power per unit area, resulting in the same amount of emitted energy as the hot light bulb filament.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solar photovoltaics are practical for individual homes, but solar thermal is only to be found in large utility-scale installations. What is the practical reason why we should not expect solar thermal installations on peoples' rooftops for electricity generation?

If a blue photon having \(3.3\) electron-volt of energy liberates an electron in silicon, whose band gap is \(1.1 \mathrm{eV}_{\prime \prime}\), what fraction of the photon's energy is "kept" by the electron once it settles down from the excess?

If we had two monochromatic (single-wavelength) light sources-a green one at \(\lambda=0.5 \mu \mathrm{m}\) and a near-infrared one at \(\lambda=1.0 \mu \mathrm{m}-\) each emitting photons at an energy rate of \(1 \mathrm{~W}, 103\) how does the number of photons emerging per second from each source compare? Is it the same number for each because both are \(1 \mathrm{~W}\) sources, or is it a different number-and by what factor, if so?

If typical insolation is \(200 \mathrm{~W} / \mathrm{m}^{2}\), how much land area would be needed for a \(15 \%\) efficient flat PV array supplying an average of \(10 \mathrm{~kW}\) of power-which is the U.S. individual share? If arranged in a square, how large is the side-length of this array? Compare its size or area to something familiar.

One way to look at solar payback time time is to note that an installed system will cost something like \(\$ 3,000\) for each \(\mathrm{kW}_{\mathrm{p}}\) (peak capacity), and that you'll produce \(x \mathrm{kWh}\) from that \(1 \mathrm{~kW}_{\mathrm{p}}\) array if your region gets \(x\) hours of full-sun- equivalent on average. Since each kWh of electricity costs something like \(\$ 0.15\), it becomes straightforward to compute the value per day as \(\$ 0.15 x\), and determine how long to match the \$3k investment. The result is independent of the actual array size, depending only on the cost per \(W_{p}\), the solar yield at your location, and the cost of electricity. What would the payback time be, in years, if the cost is \(\$ 3 / W_{p}, 17\) the yield is 6 hours per day of full-sun-equivalent, and electricity in your region costs \(\$ 0.15 / \mathrm{kWh}\) ?

See all solutions

Recommended explanations on Environmental Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free