Control rods in nuclear reactors tend to contain \({ }^{10} \mathrm{~B}\), which has a high neutron absorption cross section. \(^{81}\) What happens to this nucleus when it absorbs a neutron, and is the result stable? If not, track the decay chain until it lands on a stable nucleus.

Short Answer

Expert verified
Answer: The final stable nucleus is ${}^{11} \mathrm{~N}$.

Step by step solution

01

Write down the nuclear reaction after neutron absorption

When a \({ }^{10} \mathrm{~B}\) nucleus absorbs a neutron, we add the neutron to the existing nucleus to represent the new nucleus. In this case, it becomes \({ }^{11} \mathrm{~B}\). Hence, the initial nuclear reaction can be represented as follows: \({ }^{10} \mathrm{~B} + { }^1 \mathrm{n} \rightarrow { }^{11} \mathrm{~B}\)
02

Check the stability of the new nucleus

We need to verify whether the resulting \({ }^{11} \mathrm{~B}\) is a stable nucleus or not. Checking the stability, we find that \({ }^{11} \mathrm{~B}\) is actually unstable, undergoing beta decay.
03

Represent the beta decay for \({ }^{11} \mathrm{~B}\)

In beta decay, a neutron in the nucleus is converted to a proton, with the emission of an electron (more specifically, an electron plus an electron antineutrino). As a result, the atomic number increases, while the mass number remains the same. We write the beta decay for \({ }^{11} \mathrm{~B}\) as follows: \({ }^{11} \mathrm{~B} \rightarrow { }^{11} \mathrm{~C} + { }^{-1} \mathrm{e} + \bar{\nu}_\mathrm{e}\)
04

Check the stability of \({ }^{11} \mathrm{~C}\)

Now, the resulting nucleus is \({ }^{11} \mathrm{~C}\). We need to check if it is stable or not. If it is stable, we are done. But, in this case, we find that \({ }^{11} \mathrm{~C}\) is also unstable and undergoes beta decay as well.
05

Represent the beta decay for \({ }^{11} \mathrm{~C}\)

We repeat the process for beta decay. Writing the beta decay for \({ }^{11} \mathrm{~C}\), we get: \({ }^{11} \mathrm{~C} \rightarrow { }^{11} \mathrm{~N} + { }^{-1} \mathrm{e} + \bar{\nu}_\mathrm{e}\)
06

Check the stability of \({ }^{11} \mathrm{~N}\)

Now, we have reached \({ }^{11} \mathrm{~N}\), and we need to verify its stability. In this case, we find that \({ }^{11} \mathrm{~N}\) is a stable nucleus. Thus, we have reached a stable nucleus following the decay chain. In conclusion, the \({ }^{10} \mathrm{~B}\) nucleus undergoes the following decay chain after absorbing a neutron: \({ }^{10} \mathrm{~B} + { }^1 \mathrm{n} \rightarrow { }^{11} \mathrm{~B} \rightarrow { }^{11} \mathrm{~C} + { }^{-1} \mathrm{e} + \bar{\nu}_\mathrm{e} \rightarrow { }^{11} \mathrm{~N} + { }^{-1} \mathrm{e} + \bar{\nu}_\mathrm{e}\)

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Most popular questions from this chapter

In a year, an average American uses about \(3 \times 10^{11} \mathrm{~J}\) of energy. How much mass does this translate to via \(E=m c^{2} ?\) Rock has a density approximately 3 times that of water, translating to about \(3 \mathrm{mg}\) per cubic millimeter. So roughly how big would a chunk of rock material be to provide a year's worth of energy if converted to pure energy? Is it more like dust, a grain of sand, a pebble, a rock, a boulder, a hill, a mountain?

Since each nuclear plant delivers \(\sim 1 \mathrm{GW}\) of electrical power, at \(\sim 40 \%\) thermodynamic efficiency this means a thermal generation rate of \(2.5\) GW. How many nuclear plants would we need to supply all 18 TW of our current energy demand? Since a typical lifetime is 50 years before decommissioning, how many days, on average would it be between new plants coming online (while old ones are retired) in a steady state?

The world uses energy at a rate of \(18 \mathrm{TW}\), amounting to almost \(6 \times 10^{20}\) J per year. What is the mass-equivalent \(^{83}\) of this amount of annual energy? What context can you provide for this amount of mass?

Operating approximately 450 nuclear plants over about 60 years at a total thermal level of \(1 \mathrm{TW}\), we have had two major radioactive releases into the environment. If we went completely down the nuclear road and get all \(18 \mathrm{TW}^{89}\) this way, what rate of accidents might we expect, if the rate just scales with usage levels?

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