Which of the following is true about the fragments from \(\mathrm{a}^{235} \mathrm{U}\) fission event? a) any number of fragments ( 2 through 235 ) can be produced b) a small number of fragments will emerge ( 2 to 5 ) c) two nearly identical fragments will emerge d) two fragments of distinctly different size will emerge e) the fission is an alpha decay: a small piece having \(A=4\) is emitted

Short Answer

Expert verified
Answer: b) a small number of fragments will emerge (2 to 5).

Step by step solution

01

Understanding Fission

Fission is the process in which a nucleus splits into two or more smaller nuclei. For Uranium-235, it can undergo fission when it absorbs a neutron, forming an unstable nucleus which subsequently splits into smaller nuclei, releasing a large amount of energy in the process. The fragments produced in the fission are often accompanied by the emission of neutrons and gamma rays.
02

Analyzing Options

Now, we will analyze each option to find the correct answer. a) It is true that there can be more than two fragments, but the probability of producing a large number of fragments (more than 2 to 5) is very low. So this option is incorrect. b) This option states that a small number of fragments will emerge (2 to 5). This is the most common outcome in a fission event, and thus it is the correct answer. c) Two nearly identical fragments mean that the fission event produced two nuclei of almost equal mass. However, this is not true because fission events usually produce fragments of different size. Thus, this option is incorrect. d) Although two fragments of different sizes are more common than nearly identical fragments, the statement that "two fragments of distinctly different size will emerge" is not entirely true, as there could also be cases where three to five fragments are produced, albeit with lower probability. Thus, this option is incorrect. e) The fission of Uranium-235 is not an alpha decay. Alpha decay is a specific nuclear decay process where an unstable nucleus emits an alpha particle (consisting of 2 protons and 2 neutrons) resulting in a nucleus with a reduced atomic mass number (A) by 4 and a reduced atomic number (Z) by 2. Thus, this option is incorrect. Based on the analysis, the correct answer is: b) a small number of fragments will emerge (2 to 5).

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Most popular questions from this chapter

Since each nuclear plant delivers \(\sim 1 \mathrm{GW}\) of electrical power, at \(\sim 40 \%\) thermodynamic efficiency this means a thermal generation rate of \(2.5\) GW. How many nuclear plants would we need to supply all 18 TW of our current energy demand? Since a typical lifetime is 50 years before decommissioning, how many days, on average would it be between new plants coming online (while old ones are retired) in a steady state?

If a friend creates a nucleus whose half-life is 4 hours and gives it to you at noon, what is the probability that it will not have decayed by noon the following day?

Control rods in nuclear reactors tend to contain \({ }^{10} \mathrm{~B}\), which has a high neutron absorption cross section. \(^{81}\) What happens to this nucleus when it absorbs a neutron, and is the result stable? If not, track the decay chain until it lands on a stable nucleus.

Cosmic rays impinging on our atmosphere generate radioactive \({ }^{14} \mathrm{C}\) from \({ }^{14} \mathrm{~N}\) nuclei. \(^{78}\) These \({ }^{14} \mathrm{C}\) atoms soon team up with oxygen to form \(\mathrm{CO}_{2}\), so that plants absorbing \(\mathrm{CO}_{2}\) from the air will have about one in a trillion of their carbon atoms in this form. Animals eating these plants \(^{79}\) will also have this fraction of carbon in their bodies, until they die and stop cycling carbon into their bodies. At this point, the fraction of carbon atoms in the form of \({ }^{14} \mathrm{C}\) in the body declines, with a half life of 5,715 years. If you dig up a human skull, and discover that only one-eighth of the usual one-trillionth of carbon atoms are \({ }^{14} \mathrm{C}\), how old do you deem the skull to be?

Problem 15 indicated that we need the mass-equivalent of fewer than 10 tons 87 of material to support the world's annual energy needs. But given realities that only \(0.08 \%\) of mass is converted to energy in nuclear reactions, that only \(0.72 \%\) of natural uranium is fissile \({ }^{235} \mathrm{U}\), and that only half of the \({ }^{235} \mathrm{U}\) is retrievable \(^{88}\) and "burned" in reactors, how many tons of uranium must be mined per year to support 18 TW via conventional fission, assuming for the sake of this problem that 5 tons of mass need to convert to energy via \(E=m c^{2} ?\)

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