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Chapter 5: Problem 36

Considering the typical wavelength of light to be \(0.55 \mu \mathrm{m}\), what is a typical photon energy, in Joules, and how many photons per second emerge from a \(1 \mathrm{~W}\) light source? \(^{54}\)

Short Answer

Expert verified
Answer: To find the energy of one photon and the number of photons emitted per second, follow these steps: Step 1: Calculate the energy of one photon using the formula: $$ E = \dfrac{h * c}{\lambda} $$ Plugging in the given values, we get: $$ E = \dfrac{(6.63\times 10^{-34} \text{ Js}) * (3\times 10^8 \text{ m/s})}{0.55\times 10^{-6} \text{ m}} $$ Calculate the energy E. Step 2: Calculate the number of photons emitted per second using the formula: $$ n = \dfrac{P}{E} $$ Plugging in the given values, we get: $$ n = \dfrac{1 \text{ W}}{E} $$ Calculate the number of photons n emitted per second using the energy E found in Step 1.

Step by step solution

01

Find the energy of one photon

To find the energy of one photon, we can use the formula: $$ E = \dfrac{h * c}{\lambda} $$ Plugging in the given values: $$ E = \dfrac{(6.63\times 10^{-34} \text{ Js}) * (3\times 10^8 \text{ m/s})}{0.55\times 10^{-6} \text{ m}} $$ Calculate the energy \(E\).
02

Find the number of photons emitted per second

To find the number of photons emitted per second, we can use the formula: $$ n = \dfrac{P}{E} $$ Plugging in the given values: $$ n = \dfrac{1 \text{ W}}{E} $$ where we already found \(E\), from the previous step. Calculate the number of photons \(n\) emitted per second.

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Most popular questions from this chapter

A smaller or less active person may require only \(1,300 \mathrm{kcal}\) per day of food intake, while a larger or more active person might demand \(3,000 \mathrm{kcal}\) per day. Approximately what range of power does this spread translate to, in Watts?

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