After four half-lives, about how much radioactive parent material is left?

Short Answer

Expert verified
After four half-lives, approximately \(6.25\%\) of the radioactive parent material will remain.

Step by step solution

01

Identify the given information

Here, we are given that after four half-lives have passed, we need to find the percentage of radioactive parent material remaining. Number of half-lives (n) = 4
02

Use the exponential decay formula to calculate the amount remaining

Use the formula for exponential decay: \(Amount\ Remaining = Initial\ Amount\ (1/2)^n\) Since we want to find the percentage of radioactive parent material remaining: \(Percentage\ Remaining = (Amount\ Remaining / Initial\ Amount) * 100\) As we are not given the initial amount, we can denote it as \(P_0\). Considering that we want a percentage, we will divide the \(Amount\ Remaining\) by the initial amount, which will cancel the \(P_0\) from the equation: \(Percentage\ Remaining = \frac{P_0 * (1/2)^n}{P_0} * 100\) Simplifying the equation: \(Percentage\ Remaining = (1/2)^n * 100\)
03

Plug in the given number of half-lives and solve

With the number of half-lives (n) = 4, the equation becomes: \(Percentage\ Remaining = (1/2)^4 * 100\) Calculating the remaining percentage: \(Percentage\ Remaining = (1/16) * 100\) Multiply to get the remaining percentage: Percentage Remaining ≈ 6.25% After four half-lives, approximately 6.25% of the radioactive parent material will remain.

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