If it is assumed that all525 poker hands are equally likely, what is the probability of being dealt

(a)a flush? (A hand is said to be a flush if all 5cards are of the same suit.)

(b)one pair? (This occurs when the cards have denominations a,a,b,c,d,where a,b,c,anddare all distinct.)

(c)two pairs? (This occurs when the cards have denominations a,a,b,b,c,where a,b,and care all distinct.)

(d)three of a kind? (This occurs when the cards have denominations a,a,a,b,c,where a,b,and care all distinct.)

(e)four of a kind? (This occurs when the cards have denominationsa,a,a,a,b)

Short Answer

Expert verified

a)0.0019b)0.4225c)0.04754d)0.0211e)0.0002

Step by step solution

01

Given Information.

If it is assumed that all 525poker hands are equally likely,

02

Part (a) Explanation.

P(flush)=[(4C1)*(13C5)]/52C5=0.0019.

03

Part (b) Explanation.

P(onepair)=[(13C1)*(4C2)*)(12C3)*(4C1)*(4C1)*(4C1)]/(52C5)=0.4225.

04

Part (c) Explanation.

P(twopairs)=[(13C1)*(4C2)*(4C2)*(11C1)*(4C1)]/(52C5)=0.04754.

05

Part (d) Explanation.

P(threeofakind)=[(13Cl)*(4C3)*(12C2)*(4Cl)*(4Cl)]/(52C5)=0.0211.

06

Part (e) Explanation.

P(fourofakind)=[(13Cl)*(4C4)*(12C1)*(4Cl)]/(52C5)=0.0002.

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Most popular questions from this chapter

Five people, designated as A,B,C,D,E, are arranged in linear order. Assuming that each possible order is equally likely, what is the probability that

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