A pair of fair dice is rolled. What is the probability that the second die lands on a higher value than does the first?

Short Answer

Expert verified

512count the number of equally likely events.

Step by step solution

01

Given Information.

A pair of fair dice is rolled.

02

Explanation. 

Experiment: Two fair dice are rolled.

Question:P(seconddielandsonabiggernumber)=?

Since the dice are fair and distinct, each of the 6·6rolls is equally likely.

To enumerate the number of possible configurations in the wanted event, choose two out of 6the numbers - in 62ways. (Because each of these choices corresponds to one throw where the second dice gets a higher number)

P(second die scores higher)=626·6=1536=512

512count the number of equally likely events.

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