In how many ways can nidentical balls be distributed into rurns so that the ithurn contains at least miballs, for each i=1,...,r? Assume that ni=1rmi.

Short Answer

Expert verified

The required number of ways are =n-r-1m+r-1.

Step by step solution

01

Step 1. Given information.

It is given that,

No. of identical balls =n

No. of urns =r

The ithurn contains at least miballs, where i=1,2,3,......,r.

02

Step 2. Find the required no. of ways.

Firstly, we distribute miballs in the ithurn, where i=1,2,3,......,r.

So, the no. of balls that have been distributed=i=1rmi

The remaining balls arerole="math" localid="1648301319689" =n-i=1rmi

By proposition 6.2, there aren+r-1r-1

The distinct non-negative integer valued vectors x1,x2,.....,xrsatisfyingx1+x2+.....+xr=n

Similarly in this case we have to distribute n-i=1rmiballs in role="math" localid="1648301285511" rurns.

Therefore, it can be done inn-r-1m+r-1ways.

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