Independent trials that result in a success with probability pand a failure with probability 1-pare called Bernoulli trials. Let Pndenote the probability that n Bernoulli trials result in an even number of successes (0 being considered an even number). Show that

Pn=p1-Pn-1+(1-p)Pn-1n1

Short Answer

Expert verified

Condition upon the outcome of the first trial. Independence make the following trials, n-1Bernoulli trials.

For the step of the induction substitute explicit formula for Pninto recursive formula.

Step by step solution

01

conditions for the problems

Conditioning to the first trial can solve the problem.

If and only if one of the two disjoint situations below is true, we will get an even number of successes:

  1. The first trial was a success, and in n-1trials, an odd number of successes occurs.
  2. The first trial ended in failure, and n-1trials result in an even number of successes.
02

Independence between the trials

Because of the recursive relationship, the trials are completely independent of one another. in other words,

Pn=p1-Pn-1+qPn-1,n1

n=1is included since we anticipated 0to be an even integer, hence P0=1.

03

Derivation by Induction

In the other hand, the demonstration by induction goes like this,

n=1,1+1-2p2=q=P1

n, For a universal natural number n, we suppose that the equality holds.

n+1, SubstitutingPn=1+(1-2p)n2

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