In any given year, a male automobile policyholder will make a claim with probability pmand a female policyholder will make a claim with probability localid="1646823185045" pf,where pfpm. The fraction of the policyholders that are male is α,0<α<1.A policyholder is randomly chosen. If Aidenotes the event that this policyholder will make a claim in the year i,show that

PA2A1>PA1

Give an intuitive explanation of why the preceding inequality is true.

Short Answer

Expert verified

The inequality follows. Because from the provided data, the policyholder had a claim in a year 1.And it creates more likely that was a kind of policyholder having a larger claim probability.

Step by step solution

01

Given Information

From the given information, In any given year, a male automobile policyholder will make a claim with probability pmand a female policyholder will make a claim with probability localid="1646823204596" pf.

Here,pfpm

02

Solution of the Problem

Let Mand Fdenote the events that the policyholder is male and that the policyholder is female respectively. According to the Condition the following results are shown below.

PA2A1=PA1A2PA1

=PA1A2Mα+PA1A2F(1-α)PA1Mα+PA1F(1-α)

We get,

=pm2α+pf2(1-α)pmα+pf(1-α)

If pm2α+pf2(1-α)pmα+pf(1-α)>pmα+pf(1-α)

So being indebted will work with the second equality and prove its validity to prove our problem.

03

Computation of Probability

Show that p2mα+pf2(1-α)>pmα+pf(1-α)2Simplifying the equation, that is,

p2αm+pf2(1-α)>pmα2+pf2(1-α)2+2α(1-α)pmpf

p2α-α2m+p2,α-α2>2α-α2pmpf

Simplifying the equation,

p2+mp2>f2pmpf

pm2+p2-f2pmpf>0

We get,

pm-pf2>0Sincepmpf

04

Final Answer

The inequality follows. Because from the provided data, the policyholder had a claim in the year 1.And it creates more likely that was a kind of policyholder having a larger claim probability.

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