The number of minutes of playing time of a certain high school basketball player in a randomly chosen game is a random variable whose probability density function is given in the following figure:

Find the probability that the player plays

(a) more than 15minutes;

(b) between 20and35minutes;

(c) less than 30minutes;

(d) more than 36minutes

Short Answer

Expert verified

(a) The probability that the player plays more than 15minutes is 0.875

(b) The probability that the player plays between 20and35is 0.625

(c) The probability that the player plays less than30minutes is0.75

(d) The probability that the player plays more than36minutes is0.1

Step by step solution

01

Find the probability that the player plays more than 15 minutes (part a)

Formalize the given probability function. As may be observed from the graph,

f(x)=0.025,x[10,20)(30,40]

f(x)=0.05,x[20,30]

f(x)=0, otherwise

Xis the random variable with the density function defined P. The needed probabilities are calculated as the integrals of the density function fover the relevant intervals.

P(X>15)=1-P(X15)=1-1015f(x)dx=1-10150.025dx

=1-0.025×5=0.875

02

Find the probability that the player plays between 20 and 35 minutes (part b)

P(X(20,35))=P(X(20,30))+P(X(30,35))

=2030f(x)dx+3035f(x)dx

=0.05×10+0.025×5=0.625

03

Find the probability that the player plays less than 30 minutes (part c)

P(X<30)=1-P(X30)=1-3040f(x)dx=1-30400.025dx

=1-0.025×10=0.75

04

Find the probability that the player plays more than 36 minutes (part d)

P(X>36)=3640f(x)dx=36400.025dx=0.025×4=0.1

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Verify that the gamma density function integrates to1.

Let X and Y be independent random variables that are both equally likely to be either 1, 2, . . . ,(10)N, where N is very large. Let D denote the greatest common divisor of X and Y, and let Q k = P{D = k}.

(a) Give a heuristic argument that Q k = 1 k2 Q1. Hint: Note that in order for D to equal k, k must divide both X and Y and also X/k, and Y/k must be relatively prime. (That is, X/k, and Y/k must have a greatest common divisor equal to 1.) (b) Use part (a) to show that Q1 = P{X and Y are relatively prime} = 1 q k=1 1/k2 It is a well-known identity that !q 1 1/k2 = π2/6, so Q1 = 6/π2. (In number theory, this is known as the Legendre theorem.) (c) Now argue that Q1 = "q i=1  P2 i − 1 P2 i  where Pi is the smallest prime greater than 1. Hint: X and Y will be relatively prime if they have no common prime factors. Hence, from part (b), we see that Problem 11 of Chapter 4 is that X and Y are relatively prime if XY has no multiple prime factors.)

A standard Cauchy random variable has density function

f(x)=1π1+x2<x<

Show that if X is a standard Cauchy random variable, then 1/X is also a standard Cauchy random variable.

The time (in hours) required to repair a machine is an exponentially distributed random variable with parametersλ=12. What is

(a)the probability that a repair time exceeds2hours?

(b)the conditional probability that a repair takes at least10hours, given that its duration exceeds9hours?

Suppose that X is a normal random variable with

mean 5. If P{X > 9} = .2, approximately what is Var(X)?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free