You arrive at a bus stop at 10a.m., knowing that the bus will arrive at some time uniformly distributed between 10and 10:30.

(a) What is the probability that you will have to wait longer than 10minutes?

(b) If, at 10:15, the bus has not yet arrived, what is the probability that you will have to wait at least an additional 10 minutes?

Short Answer

Expert verified

(a) The probability that the waiting time will be longer than 10minutes is 23.

(b) The probability of waiting at least an additional 10 minutes is13.

Step by step solution

01

Part (a) Step 1. Given Information.

Here, it is given that the arrival time of bus is uniformly distributed between 10-10.30a.m.

A passenger arrives at the bus stop at 10a.m.

02

Part (a) Step 2. Determine the probability density function.

Let Xbe the random variable that represents the person's waiting time in the bus stop. Then the probability density function is given by:

fx=1b-a=130

03

Part (a) Step 3. Calculate the probability that the waiting time of passenger will be more than 10 minutes.

P(X>10)=1030f(x)dx=1030130dx=130301030=13030-10=23

Therefore, the probability that the waiting time of passenger will be more than10 minutes is23.

04

Part (b) Step 1. Calculate the probability that the waiting time of passenger will be at least additional 10 minutes.

The probability will be:

PX25X>15=P(25X30)P(X>15)

=2530f(x)dx1530f(x)dx=2530130dx1530130dx=13025301301530=13030-2513030-15=13

Therefore, the probability that the waiting time of passenger will be at least additional 10minutes is13.

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