The lifetimes of interactive computer chips produced

by a certain semiconductor manufacturer are normally distributed with parametersμ=1.4×106hours and σ=3×105hours. What is the approximate probability that abatch of 100chips will contain at least 20whose lifetimes are less than 1.8×106?

Short Answer

Expert verified

The required probability is1.

Step by step solution

01

Step 1. Given information.

Here, it is given that the lifetimes of interactive computer chips are normally distributed with parameters

μ=1.4×106hoursσ=3×105hours

02

Step 2. Find the life time of an interactive computer chip.

Let Xdenote the life time of an interactive computer chip.

PX1.8×106=PZ1.8×106-1.4×1063×105=PZ1.333=0.9082

03

Step 3. Find the probability that a batch of 100chips will contain at least 20 such chips whose life times are less than 1.8×106.

p=0.9082μ=np=100×0.9082=90.82σ=npq=90.82(1-0.9082)=2.89

PY19.5=Pz19.5-90.822.89=Pz-24.6781

Therefore, the approximate probability that a batch of 100chips will contain at least 20 such chips whose life times are less than 1.8×106is1.

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