Three points X1,X2,X3 are selected at random on a line L. What is the probability thatX2 lies between X1andX3?

Short Answer

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The probability that X2lies between X1andX3is13

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01

To find

The probability thatX2lies between X1andX3

02

Explanation

Three points to consider On a line L,X1,X2,X3are chosen at random.

The number of ways to arrange n items all at once=n!.

Total number of point=3As a result, the number of ways to arrange three points on a line is=3!=6

The possible arrangements are:

X1X2X3X1X3X2X2X1X3X2X3X1X3X1X2X3X2X1

Out of these X2liesbetweenX1andX3in2arrangements

Therefore X2liesbetweenX1andX3=26=13

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