Let X1, ... , Xn and Y1, ... , Yn be independent random vectors, with each vector being a random ordering of k ones and n − k zeros. That is, their joint probability mass functions are PX1=i1,,Xn=in=PY1=i1,,Yn=in=1nk,ij=0,1,j=1nij=k

denote the number of coordinates at which the two vectors have different values. Also, let M denote the number of values of i for which

Xi = 1, Yi = 0.

(a) RelateNtoM.

(b) What is the distribution ofM?

(c) Find E[N].

(d) Find Var(N).

Short Answer

Expert verified

a)The relation betweenNtoMisN=2M.

b) The distribution ofMis hyper geometric random variable.

c) E[N]=2k(n-k)n

d) The var(N) =4(n-k)(n-1)k1-knkn

Step by step solution

01

Part (a) - Step 1: To find

The relation between N to M

02

Part (a) - Step 2: Explanation

Given: Given that X1.....XnY1.....Ynbe independent random vectors, with each vector being a random ordering of k ones and n-k zeros. That is their joint probability mass functions arePX1=i1,,Xn=in=PY1=i1,,Yn=in=1nk,ij=0,1,j=1nij=k

N=i=1nXi-Yidenote the number of coordinates at which the two vectors have different values.

Also, let M denotes the number of values of i for whichXi=1,Yi=0

Calculation : From the given information it can written as

i=1nXi=i=1nYi

So, M denotes the number of value of i.

it followsN=2M

Hence , the relation between N to M =2M.

03

Part (b) - Step 3: To find

The distribution of M.

04

Part (b) - Step 4: Explanation

Consider the n-k co-ordinates chose Y - values are equal to 0 and call them the red coordinates. Because the k co-ordinates whose X - values are equal to 1 are equally likely to be any of the nksets of k coordinates, It follows the number of Red coordinates among these k coordinates has the same distribution as the number of Red balls chosen when one Randomly chooses k of a set n balls of which n-k are Red. Therefore, M is a Hyper geometric Random variable.

05

Part (c) - Step 5: To find

The value ofE[N]

06

Part (c) - Step 6: Explanation

Given :

Given that X1....XnY1.....Ynbe independent random vectors, with each vector being a random ordering of k ones and n-k zeros. That is their joint probability mass functions are PX1=i1,,Xn=in=PY1=i1,,Yn=in=1nk,ij=0,1,j=1nij=k

N=i=1nXi-Yidenote the number of coordinates at which the two vectors have different values.

Also, let M denotes the number of values of i for whichXi=1,Yi=0

Calculation :

E[N]=E[2M]=2E[M]E[N]=2k(n-k)n

Therefore2k(n-k)nistheE[N]

07

Part (d) -  Step 7 : To find

The value ofvar(N)

08

Part (d) - Step 8: Calculation

Calculation : Var[N]=Var[2M]=22Var[M]Var[N]=4(nk)(n1)k1knkn

Hence the value ofVar[N]=4(n-k)(n-1)k1-knkn

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