A fair die is rolled 10times. Calculate the expected sum of the10 rolls.

Short Answer

Expert verified

The expected sum of the10 rolls value are35.

Step by step solution

01

Given Information

Calculate the expected sum of the10 rolls.

Let random variable Xirepresent the number on the face of the dice, after the roll.

02

Explanation

Since there are 6numbers on a dice, the probability of getting any of the numbers is

PXi=1=16,

PXi=2=16,

PXi=3=16,

PXi=4=16,

PXi=5=16.

PXi=6=16.

03

Expected sum of the 10 rolls

Let us find the expected sum of the 10rolls.

EXi=1×PXi=1+2×PXi=2

role="math" localid="1647251498640" +3×PXi=3+4×PXi=4

role="math" localid="1647251538454" +5×PXi=5+6×PXi=6

Substitute the value,

=1×16+2×16

+3×16+4×16

+5×16+6×16.

04

Multiply the value

Multiply the value,

=16×(1+2+3+4+5+6)

=216

Divide

=72.

05

Substitute the value

Therefore, the expected sum of the 10rolls is,

E(X)=10×EXi

Substitute,

=10×72

=35.

06

Final answer

The expected sum of the10 rolls value are 35.

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Most popular questions from this chapter

In Problem 7.6, calculate the variance of the sum of the rolls.

A fair die is successively rolled. Let X and Y denote, respectively, the number of rolls necessary to obtain a 6 and a 5. Find

(a) E[X];

(b) E[XY=1];

(c) E[XY=5];

Suppose that X1and X2are independent random variables having a common mean μ. Suppose also that VarX1=σ12and VarX2=σ22. The value of μis unknown, and it is proposed that μbe estimated by a weighted average of X1and X2. That is, role="math" localid="1647423606105" λX1+(1-λ)X2will be used as an estimate of μfor some appropriate value of λ. Which value of λyields the estimate having the lowest possible variance? Explain why it is desirable to use this value of λ

A deck of n cards numbered 1 through n is thoroughly shuffled so that all possible n! orderings can be assumed to be equally likely. Suppose you are to make n guesses sequentially, where the ith one is a guess of the card in position i. Let N denote the number of correct guesses.

(a) If you are not given any information about your earlier guesses, show that for any strategy, E[N]=1.

(b) Suppose that after each guess you are shown the card that was in the position in question. What do you think is the best strategy? Show that under this strategy

E[N]=1n+1n1++11n1xdx=logn

(c) Supposethatyouaretoldaftereachguesswhetheryou are right or wrong. In this case, it can be shown that the strategy that maximizes E[N] is one that keeps on guessing the same card until you are told you are correct and then changes to a new card. For this strategy, show that

E[N]=1+12!+13!++1n!e1

Hint: For all parts, express N as the sum of indicator (that is, Bernoulli) random variables.

Gambles are independent, and each one results in the player being equally likely to win or lose 1 unit. Let W denote the net winnings of a gambler whose strategy is to stop gambling immediately after his first win. Find

(a) P{W > 0}

(b) P{W < 0}

(c) E[W]

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