Let Xbe a nonnegative random variable having a distribution function F. Show that if F¯(x)=1-F(x), then

EXn=0xn-1F¯(x)dx

Hint: Start with the identity

Xn=n0Xxn-1dx

=n0xn-1IX(x)dx

where
Ix(x)=10ifx<X otherwise

Short Answer

Expert verified

=F¯(x)
Hence EXn=n0xn-1F¯(x)dx

Step by step solution

01

Concept Introduction

Let X be a Non-negative Random variable having distribution function F.
With F¯(x)=1-F(x)

02

:Explanation

Let Xbe a Non-negative Random variable having distribution function F.
With F¯(x)=1-F(x)

03

:Explanation

Xn=n0xxn-1dx

04

Step 4:Explanation

=n0xn-1Ix(x)dx=n0xn-1Ix(x)dx=n0xn-1Ix(x)dx=n0xn-1Ix(x)dx

05

Step 5:Explanation

Where Ix(x)=10if x<Xx<X
otherwise

06

Step 6:Explanation

EIX(x)=1.P[x<X]

07

Step 7:Explanation

=P[X>x]

08

Step 8:Explanation

=1-P[Xx]=1-P[Xx]=1-P[Xx]
=1-F(x)

09

Final Answer

=F¯(x)
Hence EXn=n0xn-1F¯(x)dx

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