Use the conditional variance formula to determine the variance of a geometric random variable X having parameter p.

Short Answer

Expert verified

The variance of a geometric random variable Xhaving parameter pisVar(X)=1-pp2.

Step by step solution

01

Given Information

The variance of a geometric random variable X having parameter p.

02

Explanation

Suppose a sequence of independent Bernoulli random variables Xnn1 with the parameter of success p. Let Xmark the index of first random variable which has yielded a success. We know that Zhas Geometric distribution with parameterp. Using the formula for conditional variance, we can condition on random variable X1. We have that

Var(X)=EVarXX1+VarEXX1

EVarXX1=EEX2X1-EXX12

=PX1=0·EX2X1=0-EXX1=02+ PX1=1EX2X1=1-EXX1=12

=(1-p)EX2-E(X)2+0

=(1-p)Var(X)

03

Explanation

EXX1=1·IX1=1+1+1pIX1=0

Applying the variance,

VarEXX1=p(1-p)+1+1p2p(1-p)-2p(1-p)1+1p

Var(X)=(1-p)Var(X)+1p2p(1-p)

Var(X)=1-pp2

04

Final Answer

The variance of a geometric random variable X having parameterp isVar(X)=1-pp2.

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